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find centroid of the region bounded by y=ln(x) the axis and x=e
 one year ago
 one year ago
find centroid of the region bounded by y=ln(x) the axis and x=e
 one year ago
 one year ago

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math_proofBest ResponseYou've already chosen the best response.0
dw:1352954819183:dw
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
First, you'll need the total area. What do you get?
 one year ago

math_proofBest ResponseYou've already chosen the best response.0
you have to do double integral to find mass right?
 one year ago

math_proofBest ResponseYou've already chosen the best response.0
so it will be (e1)p?
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
Right, I assumed the very common uniform density. Sorry abuot that. "e1"? No. How did you get that?
 one year ago

math_proofBest ResponseYou've already chosen the best response.0
im confused about setting out the integrals limits
 one year ago

math_proofBest ResponseYou've already chosen the best response.0
\[\int\limits_{1}^{e}\int\limits_{0}^{\ln(x)}p dydx\]
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
\[\int\ln(x)\;dx = x\ln(x)  x + C\] (e*ln(e)  e)  (1*ln(1)  1) = e*ln(e)  e  0 + 1 = e(1)  e + 1 = ee+1 = 1
 one year ago

math_proofBest ResponseYou've already chosen the best response.0
what is that? is that a mass?
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
\[\int_{1}^{e}\int_{0}^{ln(x)}\rho\;dy\;dx = \rho\]
 one year ago

math_proofBest ResponseYou've already chosen the best response.0
for the center mass the integral will be the same?
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
It's not a matter of guesing or whether we can predict it or how we feel about it. It's just how it works out on this one,
 one year ago

math_proofBest ResponseYou've already chosen the best response.0
\[\int\limits_{1}^{e}\int\limits_{0}^{\ln(x)}xpdydx\]
 one year ago

math_proofBest ResponseYou've already chosen the best response.0
just wanna know if this is the integration
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
Yes, that is one of them.
 one year ago
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