anonymous
  • anonymous
Homework11 and LAB11answers......!
MIT 6.002 Circuits and Electronics, Spring 2007
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
p1: L=0.65mH, RL=4 ohms, RC=490Kohms 1.)1/(RC*C) + RL/L 2.)92.236 (f=650khz) 3.)4.5 4.)22 (f=1330khz) 5.)16 p2: 1.)vm*0.1=0.01 2.)Cs/Rp=2.55 3.)Cs/Rp=2.55 4.)0.8 p3: 1.)C 2.)R 3.)L 4.)4 5.)L 6.)1000 7.)1 8.)16
anonymous
  • anonymous
LAB11: 1.)0.001592 2.)1.592e-7 3.)0.0356 4.)10
anonymous
  • anonymous
hi rvamsi, what is the eq. for H11P2 part (4) ...

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Qaisersatti
  • Qaisersatti
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anonymous
  • anonymous
no wonder why i was having trouble with the ifrst part of lab 11. Those guys are idiots. They said wo=10k which means 2*pi*f=10k.. they actually meant that fresonance=10k, THEREFORE wo=62.8k
anonymous
  • anonymous
Q1 and Q2 equations please my frequency is different
anonymous
  • anonymous
hi vamsi can u please say me the equation for finding capacitor in H11Q1
anonymous
  • anonymous
for H11P1 que1 use C=1/(L*((2*3.14*f)^2))
anonymous
  • anonymous
Hello there fellas, can't get H11P2 - part 4 and 5. can anybody sort this for me? I have f=1150 kHz. Appreciate it
anonymous
  • anonymous
problem 2 or problem 1?
anonymous
  • anonymous
Oops, sorry, P1 it is. part 4 and 5
anonymous
  • anonymous
At f = 1150 kHz, finding capacitance and badwidth
anonymous
  • anonymous
ans for 4=29.496 ans for 5=75.343
anonymous
  • anonymous
please select best response if it is correct if not pls respond i will try again
anonymous
  • anonymous
Ahh, thank you Mr. Siva, part 4 is correct but nit agreeing on 5. the one that asks for bandwidth. Do you know what could be wrong? Thank you sir
anonymous
  • anonymous
oops small mistake ans for 5 is 11.991
anonymous
  • anonymous
Grrreeeat! Thank you very much. You have helped me ace it. :)
anonymous
  • anonymous
No mention if u are done with H12 P3 please give me the formula or equations for that
anonymous
  • anonymous
Plz can you tell me the formula to calculate bandwidth for part 3 of HW 11
anonymous
  • anonymous
and I cant understand how to find Cp..
anonymous
  • anonymous
hey what is the need of BW in P3
anonymous
  • anonymous
pls give me the Q no
anonymous
  • anonymous
BW for part 3 of H11P1...but I got it...I wasn't dividing the answer with 2*pie so....but now I am stuck in H11P2 last part
anonymous
  • anonymous
P1 2&3 f= 1010 4&5 1030 khz
anonymous
  • anonymous
b) (thats the formula = 1/(2*pi*f)^(2)*L) c) (thats the formula = 1/(RC*C) + RL/L) d) (thats the formula = 1/(2*pi*f)^(2)*L) e) c) (thats the formula = 1/(RC*C) + RL/L) H11P2 d) 0.1*VM(t)
anonymous
  • anonymous
Click best if helped I got 38.2 and for b and d of h11p2. Cant get right answer for c and e Plz Help Rc = 490k, RL = 4 L = .65mH f= 1010 and 1030 rsp.
anonymous
  • anonymous
Coolampio, I try to use the formula 1/(RC*C) + RL/L) in c) and e), but I've got a wrong answer. my f=740kHz & 1660kHz. I've got capacitances 71pF & 14pF respectively. But in questions c & e I've got 35kHz and 151kHz, it's wrong.
anonymous
  • anonymous
For d, I got 36.7 forgot to mention up having pblem with same ones my self
anonymous
  • anonymous
I find it! For c) & e) parts of h11p1 we need divide the formula: "1/(RC*C) + RL/L" by 2pi.
anonymous
  • anonymous
What is the bandwidth, in 770 kHz, of the tank at kHz?
anonymous
  • anonymous
Mahmoudmosad, your bandwidth is 5.9kHz

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