Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Homework11 and LAB11answers......!

MIT 6.002 Circuits and Electronics, Spring 2007
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
p1: L=0.65mH, RL=4 ohms, RC=490Kohms 1.)1/(RC*C) + RL/L 2.)92.236 (f=650khz) 3.)4.5 4.)22 (f=1330khz) 5.)16 p2: 1.)vm*0.1=0.01 2.)Cs/Rp=2.55 3.)Cs/Rp=2.55 4.)0.8 p3: 1.)C 2.)R 3.)L 4.)4 5.)L 6.)1000 7.)1 8.)16
LAB11: 1.)0.001592 2.)1.592e-7 3.)0.0356 4.)10
hi rvamsi, what is the eq. for H11P2 part (4) ...

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

1 Attachment
no wonder why i was having trouble with the ifrst part of lab 11. Those guys are idiots. They said wo=10k which means 2*pi*f=10k.. they actually meant that fresonance=10k, THEREFORE wo=62.8k
Q1 and Q2 equations please my frequency is different
hi vamsi can u please say me the equation for finding capacitor in H11Q1
for H11P1 que1 use C=1/(L*((2*3.14*f)^2))
Hello there fellas, can't get H11P2 - part 4 and 5. can anybody sort this for me? I have f=1150 kHz. Appreciate it
problem 2 or problem 1?
Oops, sorry, P1 it is. part 4 and 5
At f = 1150 kHz, finding capacitance and badwidth
ans for 4=29.496 ans for 5=75.343
please select best response if it is correct if not pls respond i will try again
Ahh, thank you Mr. Siva, part 4 is correct but nit agreeing on 5. the one that asks for bandwidth. Do you know what could be wrong? Thank you sir
oops small mistake ans for 5 is 11.991
Grrreeeat! Thank you very much. You have helped me ace it. :)
No mention if u are done with H12 P3 please give me the formula or equations for that
Plz can you tell me the formula to calculate bandwidth for part 3 of HW 11
and I cant understand how to find Cp..
hey what is the need of BW in P3
pls give me the Q no
BW for part 3 of H11P1...but I got it...I wasn't dividing the answer with 2*pie so....but now I am stuck in H11P2 last part
P1 2&3 f= 1010 4&5 1030 khz
b) (thats the formula = 1/(2*pi*f)^(2)*L) c) (thats the formula = 1/(RC*C) + RL/L) d) (thats the formula = 1/(2*pi*f)^(2)*L) e) c) (thats the formula = 1/(RC*C) + RL/L) H11P2 d) 0.1*VM(t)
Click best if helped I got 38.2 and for b and d of h11p2. Cant get right answer for c and e Plz Help Rc = 490k, RL = 4 L = .65mH f= 1010 and 1030 rsp.
Coolampio, I try to use the formula 1/(RC*C) + RL/L) in c) and e), but I've got a wrong answer. my f=740kHz & 1660kHz. I've got capacitances 71pF & 14pF respectively. But in questions c & e I've got 35kHz and 151kHz, it's wrong.
For d, I got 36.7 forgot to mention up having pblem with same ones my self
I find it! For c) & e) parts of h11p1 we need divide the formula: "1/(RC*C) + RL/L" by 2pi.
What is the bandwidth, in 770 kHz, of the tank at kHz?
Mahmoudmosad, your bandwidth is 5.9kHz

Not the answer you are looking for?

Search for more explanations.

Ask your own question