Homework11 and LAB11answers......!

- anonymous

Homework11 and LAB11answers......!

- chestercat

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- anonymous

p1: L=0.65mH, RL=4 ohms, RC=490Kohms
1.)1/(RC*C) + RL/L
2.)92.236 (f=650khz)
3.)4.5
4.)22 (f=1330khz)
5.)16
p2:
1.)vm*0.1=0.01
2.)Cs/Rp=2.55
3.)Cs/Rp=2.55
4.)0.8
p3:
1.)C
2.)R
3.)L
4.)4
5.)L
6.)1000
7.)1
8.)16

- anonymous

LAB11:
1.)0.001592
2.)1.592e-7
3.)0.0356
4.)10

- anonymous

hi rvamsi, what is the eq. for H11P2 part (4) ...

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- Qaisersatti

##### 1 Attachment

- anonymous

no wonder why i was having trouble with the ifrst part of lab 11. Those guys are idiots. They said wo=10k which means 2*pi*f=10k.. they actually meant that fresonance=10k, THEREFORE wo=62.8k

- anonymous

Q1 and Q2 equations please my frequency is different

- anonymous

hi vamsi can u please say me the equation for finding capacitor in H11Q1

- anonymous

for H11P1
que1
use C=1/(L*((2*3.14*f)^2))

- anonymous

Hello there fellas, can't get H11P2 - part 4 and 5. can anybody sort this for me? I have f=1150 kHz. Appreciate it

- anonymous

problem 2 or problem 1?

- anonymous

Oops, sorry, P1 it is. part 4 and 5

- anonymous

At f = 1150 kHz, finding capacitance and badwidth

- anonymous

ans for 4=29.496
ans for 5=75.343

- anonymous

please select best response if it is correct if not pls respond i will try again

- anonymous

Ahh, thank you Mr. Siva, part 4 is correct but nit agreeing on 5. the one that asks for bandwidth. Do you know what could be wrong? Thank you sir

- anonymous

oops small mistake ans for 5 is 11.991

- anonymous

Grrreeeat! Thank you very much. You have helped me ace it. :)

- anonymous

No mention
if u are done with H12 P3 please give me the formula or equations for that

- anonymous

Plz can you tell me the formula to calculate bandwidth for part 3 of HW 11

- anonymous

and I cant understand how to find Cp..

- anonymous

hey what is the need of BW in P3

- anonymous

pls give me the Q no

- anonymous

BW for part 3 of H11P1...but I got it...I wasn't dividing the answer with 2*pie so....but now I am stuck in H11P2 last part

- anonymous

P1 2&3 f= 1010 4&5 1030 khz

- anonymous

b) (thats the formula = 1/(2*pi*f)^(2)*L)
c) (thats the formula = 1/(RC*C) + RL/L)
d) (thats the formula = 1/(2*pi*f)^(2)*L)
e) c) (thats the formula = 1/(RC*C) + RL/L)
H11P2
d) 0.1*VM(t)

- anonymous

Click best if helped
I got 38.2 and for b and d of h11p2. Cant get right answer for c and e Plz Help
Rc = 490k, RL = 4 L = .65mH f= 1010 and 1030 rsp.

- anonymous

Coolampio, I try to use the formula 1/(RC*C) + RL/L) in c) and e), but I've got a wrong answer. my f=740kHz & 1660kHz. I've got capacitances 71pF & 14pF respectively. But in questions c & e I've got 35kHz and 151kHz, it's wrong.

- anonymous

For d, I got 36.7 forgot to mention up
having pblem with same ones my self

- anonymous

I find it! For c) & e) parts of h11p1 we need divide the formula: "1/(RC*C) + RL/L" by 2pi.

- anonymous

What is the bandwidth, in 770 kHz, of the tank at kHz?

- anonymous

Mahmoudmosad, your bandwidth is 5.9kHz

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