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find the antiderivative of (3x+10)(3x-10)

Calculus1
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we havent learned rules of multiplication when it comes to antiderivatives yet...so not sure how to handle it
you have to expand it then you do it like the other ones. \[9x^2-100\]
\[\frac{ 9x^3 }{ 3 }+100x +C\]

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Other answers:

oh ok so the antiderivative is 3x^3-100x
ya plus the constant
thx!
-100 not +100 sorry
i have another question about antiderivatives if you could help please :)
sure
the antiderivative of (x^.5+.5x^-.5)2 (the square root of x plus half times square root of x (in denominator))squared
because if i do it the other way you did before (add the the expoenent) and divide by it.....it doesnt work because when you take the derivative you gotta take it of the inside function as well
how bout if you distribute the ^2 ?
x^2.5+.5x^1.5
then you can do it like normal
oooo ok thx
wouldnt you multiply the 2 not add it .....so it would be x+.5x^-1
nah think of 10^2 * 10^2 = 100*100=10,000 = 10^4
or 10^4* 10^2 = 10,000 * 100 = 1,000,000 = 10^6
but thats because they have the same base.....(a^x)^y = a^xy not a^(x+y)
x^2 =(x)^2 = (x)x it's all the same
pull out your calculator and try some examples just plug in any number for x
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3x^3-100x+constant

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