anonymous
  • anonymous
find the antiderivative of (3x+10)(3x-10)
Calculus1
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
we havent learned rules of multiplication when it comes to antiderivatives yet...so not sure how to handle it
Jusaquikie
  • Jusaquikie
you have to expand it then you do it like the other ones. \[9x^2-100\]
Jusaquikie
  • Jusaquikie
\[\frac{ 9x^3 }{ 3 }+100x +C\]

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anonymous
  • anonymous
oh ok so the antiderivative is 3x^3-100x
anonymous
  • anonymous
ya plus the constant
anonymous
  • anonymous
thx!
Jusaquikie
  • Jusaquikie
-100 not +100 sorry
anonymous
  • anonymous
i have another question about antiderivatives if you could help please :)
Jusaquikie
  • Jusaquikie
sure
anonymous
  • anonymous
the antiderivative of (x^.5+.5x^-.5)2 (the square root of x plus half times square root of x (in denominator))squared
anonymous
  • anonymous
because if i do it the other way you did before (add the the expoenent) and divide by it.....it doesnt work because when you take the derivative you gotta take it of the inside function as well
Jusaquikie
  • Jusaquikie
how bout if you distribute the ^2 ?
Jusaquikie
  • Jusaquikie
x^2.5+.5x^1.5
Jusaquikie
  • Jusaquikie
then you can do it like normal
anonymous
  • anonymous
oooo ok thx
anonymous
  • anonymous
wouldnt you multiply the 2 not add it .....so it would be x+.5x^-1
Jusaquikie
  • Jusaquikie
nah think of 10^2 * 10^2 = 100*100=10,000 = 10^4
Jusaquikie
  • Jusaquikie
or 10^4* 10^2 = 10,000 * 100 = 1,000,000 = 10^6
anonymous
  • anonymous
but thats because they have the same base.....(a^x)^y = a^xy not a^(x+y)
Jusaquikie
  • Jusaquikie
x^2 =(x)^2 = (x)x it's all the same
Jusaquikie
  • Jusaquikie
pull out your calculator and try some examples just plug in any number for x
anonymous
  • anonymous
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anonymous
  • anonymous
3x^3-100x+constant

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