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## anonymous 4 years ago center of mass of the upper half(y>0 of the disk bounded by the circle x^2+y^2=4 with p(x,y)=1+y/2

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1. anonymous

is the integral $\int\limits_{-2}^{2}\int\limits_{0}^{2+x} 1+\frac{ y }{ 2 }dydx$

2. anonymous

Do the inner integral first.$\int\limits_{0}^{2+x}1dy +\frac{ 1 }{ 2 } \int\limits_{0}^{2+x}ydy$ Do u know how to integrate?

3. anonymous

yeah

4. anonymous

how did you get that though?

5. anonymous

Properties of integration allows you to do this: $\int\limits_{0}^{2+x}1+\frac{ y }{ 2 }dy = \int\limits_{0}^{2+x}1dy + \int\limits_{0}^{2+x}\frac{ y }{ 2 }dy$

6. anonymous

Are u there?

7. anonymous

is that right what philo wrote? thats for My right? do i have to do it for Mx too?

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