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The Coefficient of kinetic friction between the tires of your car and the roadway is "μ". (a) If your initial speed is "v" and you lock your tires during breaking, how far do you skid? (b) What is the stopping distance for a truck with twice the mass of you car, assuming same initial speed and coefficient of kinetic friction.
I'm stuck on (b), my mass cancels out every time, but that doesn't seem right
 one year ago
 one year ago
The Coefficient of kinetic friction between the tires of your car and the roadway is "μ". (a) If your initial speed is "v" and you lock your tires during breaking, how far do you skid? (b) What is the stopping distance for a truck with twice the mass of you car, assuming same initial speed and coefficient of kinetic friction. I'm stuck on (b), my mass cancels out every time, but that doesn't seem right
 one year ago
 one year ago

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ShadowysBest ResponseYou've already chosen the best response.0
Your mass is supposed to cancel out. Note that the distance formulas do not have mass in them and that in the workkinetic energy theorem, there is no other force except friction. Also: \(F_f = ma\) \(\mu_s mg = ma\) \(a=\mu_s g\) Don't worry about it.:)
 one year ago

Jan_EEBest ResponseYou've already chosen the best response.0
Thanks alot. I solved a and i got (V^2)/19.6μ. Help me confirm is it is correct
 one year ago

ShadowysBest ResponseYou've already chosen the best response.0
Yup! :) That's the distance.
 one year ago

Jan_EEBest ResponseYou've already chosen the best response.0
Pls helpppp i have another question. Do i just post it here or there is somewhere else i could post pls?
 one year ago

ShadowysBest ResponseYou've already chosen the best response.0
Close the question and post a new one. This way more people will take notice of it :)
 one year ago
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