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anonymous
 3 years ago
The Coefficient of kinetic friction between the tires of your car and the roadway is "μ". (a) If your initial speed is "v" and you lock your tires during breaking, how far do you skid? (b) What is the stopping distance for a truck with twice the mass of you car, assuming same initial speed and coefficient of kinetic friction.
I'm stuck on (b), my mass cancels out every time, but that doesn't seem right
anonymous
 3 years ago
The Coefficient of kinetic friction between the tires of your car and the roadway is "μ". (a) If your initial speed is "v" and you lock your tires during breaking, how far do you skid? (b) What is the stopping distance for a truck with twice the mass of you car, assuming same initial speed and coefficient of kinetic friction. I'm stuck on (b), my mass cancels out every time, but that doesn't seem right

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Your mass is supposed to cancel out. Note that the distance formulas do not have mass in them and that in the workkinetic energy theorem, there is no other force except friction. Also: \(F_f = ma\) \(\mu_s mg = ma\) \(a=\mu_s g\) Don't worry about it.:)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks alot. I solved a and i got (V^2)/19.6μ. Help me confirm is it is correct

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yup! :) That's the distance.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Pls helpppp i have another question. Do i just post it here or there is somewhere else i could post pls?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Close the question and post a new one. This way more people will take notice of it :)
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