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Jan_EE Group Title

The Coefficient of kinetic friction between the tires of your car and the roadway is "μ". (a) If your initial speed is "v" and you lock your tires during breaking, how far do you skid? (b) What is the stopping distance for a truck with twice the mass of you car, assuming same initial speed and coefficient of kinetic friction. I'm stuck on (b), my mass cancels out every time, but that doesn't seem right

  • 2 years ago
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  1. Shadowys Group Title
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    Your mass is supposed to cancel out. Note that the distance formulas do not have mass in them and that in the work-kinetic energy theorem, there is no other force except friction. Also: \(F_f = ma\) \(\mu_s mg = ma\) \(a=\mu_s g\) Don't worry about it.:)

    • 2 years ago
  2. Jan_EE Group Title
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    Thanks alot. I solved a and i got (V^2)/19.6μ. Help me confirm is it is correct

    • 2 years ago
  3. Shadowys Group Title
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    Yup! :) That's the distance.

    • 2 years ago
  4. Jan_EE Group Title
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    thks a whole lot

    • 2 years ago
  5. Shadowys Group Title
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    You're welcome :)

    • 2 years ago
  6. Jan_EE Group Title
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    Pls helpppp i have another question. Do i just post it here or there is somewhere else i could post pls?

    • 2 years ago
  7. Shadowys Group Title
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    Close the question and post a new one. This way more people will take notice of it :)

    • 2 years ago
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