hba
  • hba
Limit Question.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
hba
  • hba
\[\lim_{x \rightarrow 0}\frac{ \sin2x }{ \sin3x }\]
anonymous
  • anonymous
2/3
hba
  • hba
Please Explain :(

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
ok
anonymous
  • anonymous
one min
anonymous
  • anonymous
since you have indeterminate form, you have to use L'hospital rule
anonymous
  • anonymous
then when you do derivative you get \[\frac{ 2\cos2x }{ 3\cos3x }\]
hba
  • hba
I dont know l hospitals rule.
anonymous
  • anonymous
you don't?
anonymous
  • anonymous
you know like squeeze theorem?
hba
  • hba
Please teach me how to solve it,i am helpless :(
anonymous
  • anonymous
oki so there are couple cases when you have indeterminate form, for example 0/0 , inf/inf
anonymous
  • anonymous
so what you do then is basically take the derivative of the top and the bottom
anonymous
  • anonymous
for example \[\lim_{x \rightarrow 1} \frac{ x^3+x^2=2x }{ x-1 }\]
anonymous
  • anonymous
it suppose to be x^3+x^2-2x
anonymous
  • anonymous
so if you plug 1 in you get 0/0 which is indeterminate as it has no meaning. so you have to apply l'hospital, derivative of the top and bottom

Looking for something else?

Not the answer you are looking for? Search for more explanations.