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hba Group TitleBest ResponseYou've already chosen the best response.0
\[\lim_{x \rightarrow 0}\frac{ \sin2x }{ \sin3x }\]
 one year ago

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Please Explain :(
 one year ago

math_proof Group TitleBest ResponseYou've already chosen the best response.0
one min
 one year ago

math_proof Group TitleBest ResponseYou've already chosen the best response.0
since you have indeterminate form, you have to use L'hospital rule
 one year ago

math_proof Group TitleBest ResponseYou've already chosen the best response.0
then when you do derivative you get \[\frac{ 2\cos2x }{ 3\cos3x }\]
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
I dont know l hospitals rule.
 one year ago

math_proof Group TitleBest ResponseYou've already chosen the best response.0
you don't?
 one year ago

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you know like squeeze theorem?
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
Please teach me how to solve it,i am helpless :(
 one year ago

math_proof Group TitleBest ResponseYou've already chosen the best response.0
oki so there are couple cases when you have indeterminate form, for example 0/0 , inf/inf
 one year ago

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so what you do then is basically take the derivative of the top and the bottom
 one year ago

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for example \[\lim_{x \rightarrow 1} \frac{ x^3+x^2=2x }{ x1 }\]
 one year ago

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it suppose to be x^3+x^22x
 one year ago

math_proof Group TitleBest ResponseYou've already chosen the best response.0
so if you plug 1 in you get 0/0 which is indeterminate as it has no meaning. so you have to apply l'hospital, derivative of the top and bottom
 one year ago
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