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hbaBest ResponseYou've already chosen the best response.0
\[\lim_{x \rightarrow 0}\frac{ \sin2x }{ \sin3x }\]
 one year ago

math_proofBest ResponseYou've already chosen the best response.0
since you have indeterminate form, you have to use L'hospital rule
 one year ago

math_proofBest ResponseYou've already chosen the best response.0
then when you do derivative you get \[\frac{ 2\cos2x }{ 3\cos3x }\]
 one year ago

hbaBest ResponseYou've already chosen the best response.0
I dont know l hospitals rule.
 one year ago

math_proofBest ResponseYou've already chosen the best response.0
you know like squeeze theorem?
 one year ago

hbaBest ResponseYou've already chosen the best response.0
Please teach me how to solve it,i am helpless :(
 one year ago

math_proofBest ResponseYou've already chosen the best response.0
oki so there are couple cases when you have indeterminate form, for example 0/0 , inf/inf
 one year ago

math_proofBest ResponseYou've already chosen the best response.0
so what you do then is basically take the derivative of the top and the bottom
 one year ago

math_proofBest ResponseYou've already chosen the best response.0
for example \[\lim_{x \rightarrow 1} \frac{ x^3+x^2=2x }{ x1 }\]
 one year ago

math_proofBest ResponseYou've already chosen the best response.0
it suppose to be x^3+x^22x
 one year ago

math_proofBest ResponseYou've already chosen the best response.0
so if you plug 1 in you get 0/0 which is indeterminate as it has no meaning. so you have to apply l'hospital, derivative of the top and bottom
 one year ago
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