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hba
 3 years ago
Limit Question.
hba
 3 years ago
Limit Question.

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hba
 3 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 0}\frac{ \sin2x }{ \sin3x }\]

math_proof
 3 years ago
Best ResponseYou've already chosen the best response.0since you have indeterminate form, you have to use L'hospital rule

math_proof
 3 years ago
Best ResponseYou've already chosen the best response.0then when you do derivative you get \[\frac{ 2\cos2x }{ 3\cos3x }\]

hba
 3 years ago
Best ResponseYou've already chosen the best response.0I dont know l hospitals rule.

math_proof
 3 years ago
Best ResponseYou've already chosen the best response.0you know like squeeze theorem?

hba
 3 years ago
Best ResponseYou've already chosen the best response.0Please teach me how to solve it,i am helpless :(

math_proof
 3 years ago
Best ResponseYou've already chosen the best response.0oki so there are couple cases when you have indeterminate form, for example 0/0 , inf/inf

math_proof
 3 years ago
Best ResponseYou've already chosen the best response.0so what you do then is basically take the derivative of the top and the bottom

math_proof
 3 years ago
Best ResponseYou've already chosen the best response.0for example \[\lim_{x \rightarrow 1} \frac{ x^3+x^2=2x }{ x1 }\]

math_proof
 3 years ago
Best ResponseYou've already chosen the best response.0it suppose to be x^3+x^22x

math_proof
 3 years ago
Best ResponseYou've already chosen the best response.0so if you plug 1 in you get 0/0 which is indeterminate as it has no meaning. so you have to apply l'hospital, derivative of the top and bottom
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