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Batman_ProtectorofGotham

  • 3 years ago

Find the limit.

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  1. rob1525
    • 3 years ago
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    At this point its infinity. ;)

  2. Batman_ProtectorofGotham
    • 3 years ago
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    \[\lim_{x \rightarrow 0} (3x+2+(1/x^2))\]

  3. math_proof
    • 3 years ago
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    thats a interesting one :p

  4. rob1525
    • 3 years ago
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    I would multiply the whole function by x^2 to get it out of the denomenator then plug 0 in for x.

  5. math_proof
    • 3 years ago
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    are you allowed to do this?

  6. math_proof
    • 3 years ago
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    i don't think you can

  7. rob1525
    • 3 years ago
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    actually no. Limit does not exist. sorry.

  8. rob1525
    • 3 years ago
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    L[x:0,3x+2+((1)/(x^(2)))]

  9. math_proof
    • 3 years ago
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    its infinity right?

  10. math_proof
    • 3 years ago
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    wow batman is not even here, but we're here seating and figuring out someones problem

  11. rob1525
    • 3 years ago
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    ;)

  12. rob1525
    • 3 years ago
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    I graphed it, looks like it goes to positive infinity.

  13. rob1525
    • 3 years ago
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    Okay i checked with calculator function and both forms confirm that it goes to infinity.

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