anonymous
  • anonymous
differentiate 1 over 2^t
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
what? how can I do that..... there all part of one fraction
anonymous
  • anonymous
the answer is -2^(-t) ln 2. but i want to know how to get that answer?
anonymous
  • anonymous
I don't really understand about that..

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anonymous
  • anonymous
first take log log 2^-t= -t (ln2)
anonymous
  • anonymous
wwhats on other side ?
anonymous
  • anonymous
it same when we differentiate the exponent.. for example: e^-x solution: e^-x.-1.ln e = e^x... for this problem u should be let exponent to be 2.. so the solution: 2^-t.-1.ln 2 =-2^-t ln 2
anonymous
  • anonymous
did u get it?
anonymous
  • anonymous
not so.. pls explain further tq..
anonymous
  • anonymous
Ahh...I know it...thank you @sha0403
anonymous
  • anonymous
how there is ln 2? and not ln 2^t?
anonymous
  • anonymous
because it known as formula.. have u see my solution of the exponent? we must let e to be 2 in 2^-t
anonymous
  • anonymous
ohh yes. now i can recall back. TQVM sha :)
anonymous
  • anonymous
welcome :)

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