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nsmuni

  • 3 years ago

differentiate 1 over 2^t

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  1. DJVJ
    • 3 years ago
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    what? how can I do that..... there all part of one fraction

  2. nsmuni
    • 3 years ago
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    the answer is -2^(-t) ln 2. but i want to know how to get that answer?

  3. DJVJ
    • 3 years ago
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    I don't really understand about that..

  4. 03225186213
    • 3 years ago
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    first take log log 2^-t= -t (ln2)

  5. 03225186213
    • 3 years ago
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    wwhats on other side ?

  6. sha0403
    • 3 years ago
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    it same when we differentiate the exponent.. for example: e^-x solution: e^-x.-1.ln e = e^x... for this problem u should be let exponent to be 2.. so the solution: 2^-t.-1.ln 2 =-2^-t ln 2

  7. sha0403
    • 3 years ago
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    did u get it?

  8. nsmuni
    • 3 years ago
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    not so.. pls explain further tq..

  9. DJVJ
    • 3 years ago
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    Ahh...I know it...thank you @sha0403

  10. nsmuni
    • 3 years ago
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    how there is ln 2? and not ln 2^t?

  11. sha0403
    • 3 years ago
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    because it known as formula.. have u see my solution of the exponent? we must let e to be 2 in 2^-t

  12. nsmuni
    • 3 years ago
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    ohh yes. now i can recall back. TQVM sha :)

  13. sha0403
    • 3 years ago
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    welcome :)

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