A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

Jonask
 2 years ago
Best ResponseYou've already chosen the best response.1\[\lim_{x \rightarrow 0}\frac{ \sin(e^{x^2}1) }{ x^2 }\]

DJVJ
 2 years ago
Best ResponseYou've already chosen the best response.0you can find answers in algebra books..

shubhamsrg
 2 years ago
Best ResponseYou've already chosen the best response.1multiply divide by e^(x^2) 1 to directly reach the ans..

shubhamsrg
 2 years ago
Best ResponseYou've already chosen the best response.1as we know these things : 1) e^(x^2) 1 > 0 ,for x>0 2)e^x  1 /x = 1 for x>0 3) sin x / x = 1 for x>0 hope that;d help..

jishan
 2 years ago
Best ResponseYou've already chosen the best response.0simply apply L HOSPITAL rule.

Jonask
 2 years ago
Best ResponseYou've already chosen the best response.1it says without the rule,i did this \[\frac{\sin(x^2(\frac{ e^{x^2}1 }{ x^2 }))}{x^2}\] since\[\lim_{h \rightarrow 0} \frac{e^h1}{h}=1\]\[\frac{\sin (x^2(1))}{x^2}=1\]
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.