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reeny1996

if F(x)=tanx, then fprime(pi/6)=

  • one year ago
  • one year ago

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  1. Shadowys
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    Have you differentiated F(x) and then sub'ed \(\frac{\pi}{6}\) into it?

    • one year ago
  2. waterineyes
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    Do you know the derivative of tan(x) ??

    • one year ago
  3. reeny1996
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    i kno the differvative is secxtanx but i dont know where to go frm there :/

    • one year ago
  4. waterineyes
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    Yes, than just replace x by pi/6..

    • one year ago
  5. reeny1996
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    (2\[\sqrt{3}\]/3 and \[\sqrt{3}\]/3

    • one year ago
  6. waterineyes
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    \[F'(\frac{\pi}{6}) = \sec(\frac{\pi}{6}) \cdot \tan(\frac{\pi}{6})\]

    • one year ago
  7. reeny1996
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    igot tht part

    • one year ago
  8. waterineyes
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    What is the value of : \[\sec (\frac{\pi}{6})\]

    • one year ago
  9. reeny1996
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    2root3/3

    • one year ago
  10. waterineyes
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    Yes and what is for tan(pi/6) = ??

    • one year ago
  11. reeny1996
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    root3/3

    • one year ago
  12. waterineyes
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    Wait, derivative of tan(x) isn't it sec^2(x) ??

    • one year ago
  13. reeny1996
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    its not ?

    • one year ago
  14. waterineyes
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    \[\frac{d}{dx} \tan(x) = \sec^2(x)\]

    • one year ago
  15. reeny1996
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    thts y im getting the wrong answer

    • one year ago
  16. reeny1996
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    thank you

    • one year ago
  17. waterineyes
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    You were doing the derivative of sec(x)..

    • one year ago
  18. reeny1996
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    yea

    • one year ago
  19. waterineyes
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    \[\frac{d}{dx}\sec(x) = \sec(x) \cdot \tan(x)\] It is okay and sorry from my side too, I also got confused.. And you are welcome dear..

    • one year ago
  20. reeny1996
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    ok idk how to combine the 2 radicals

    • one year ago
  21. waterineyes
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    Where ??

    • one year ago
  22. reeny1996
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    sec^2

    • one year ago
  23. waterineyes
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    \[F'(\frac{\pi}{6}) = \sec^2(\frac{\pi}{6})\]

    • one year ago
  24. reeny1996
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    yea

    • one year ago
  25. reeny1996
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    |dw:1352970940060:dw|

    • one year ago
  26. waterineyes
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    \[\implies \frac{2 \sqrt{3}}{3} \times \frac{2\sqrt{3}}{3} \implies ??\]

    • one year ago
  27. waterineyes
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    This is simple multiplication and division now...

    • one year ago
  28. reeny1996
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    i know but im not getting the right answer

    • one year ago
  29. reeny1996
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    4

    • one year ago
  30. waterineyes
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    What are you getting tell me first...

    • one year ago
  31. waterineyes
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    Its not 4... You are missing something.

    • one year ago
  32. waterineyes
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    \[\sqrt{3} \times \sqrt{3} = ??\]

    • one year ago
  33. reeny1996
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    2 times 2=4 root3 times root 3= 3 4 times 3 =12 12 divide3 =4

    • one year ago
  34. waterineyes
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    12 divided by 3 ??? Are you sure in denominator it is 3 ??

    • one year ago
  35. reeny1996
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    im not too good with my unit circle

    • one year ago
  36. waterineyes
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    Dear, what will you get when you will square 3 ??

    • one year ago
  37. reeny1996
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    9

    • one year ago
  38. waterineyes
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    Check the colored things here : \[\frac{2 \sqrt{3}}{\color{red}{3}} \times \frac{2 \sqrt{3}}{\color{red}{3}} = ??\]

    • one year ago
  39. reeny1996
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    9

    • one year ago
  40. waterineyes
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    Yes it is 12 divided by 9 and not 3.. So what will you get now ??

    • one year ago
  41. reeny1996
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    ohhhhhh

    • one year ago
  42. reeny1996
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    4/3

    • one year ago
  43. reeny1996
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    i was thinking addition

    • one year ago
  44. reeny1996
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    my mistake...srry if i took up yhur time

    • one year ago
  45. waterineyes
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    It is okay but be careful from next time... These are called "Silly Mistakes..." Ok, now concentrate more on new problems...

    • one year ago
  46. waterineyes
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    It is okay..

    • one year ago
  47. reeny1996
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    thanks a lot :)))

    • one year ago
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