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anonymous
 4 years ago
if F(x)=tanx, then fprime(pi/6)=
anonymous
 4 years ago
if F(x)=tanx, then fprime(pi/6)=

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Have you differentiated F(x) and then sub'ed \(\frac{\pi}{6}\) into it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do you know the derivative of tan(x) ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i kno the differvative is secxtanx but i dont know where to go frm there :/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes, than just replace x by pi/6..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(2\[\sqrt{3}\]/3 and \[\sqrt{3}\]/3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[F'(\frac{\pi}{6}) = \sec(\frac{\pi}{6}) \cdot \tan(\frac{\pi}{6})\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What is the value of : \[\sec (\frac{\pi}{6})\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes and what is for tan(pi/6) = ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Wait, derivative of tan(x) isn't it sec^2(x) ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{d}{dx} \tan(x) = \sec^2(x)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thts y im getting the wrong answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You were doing the derivative of sec(x)..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{d}{dx}\sec(x) = \sec(x) \cdot \tan(x)\] It is okay and sorry from my side too, I also got confused.. And you are welcome dear..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok idk how to combine the 2 radicals

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[F'(\frac{\pi}{6}) = \sec^2(\frac{\pi}{6})\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1352970940060:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\implies \frac{2 \sqrt{3}}{3} \times \frac{2\sqrt{3}}{3} \implies ??\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0This is simple multiplication and division now...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i know but im not getting the right answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What are you getting tell me first...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Its not 4... You are missing something.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{3} \times \sqrt{3} = ??\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02 times 2=4 root3 times root 3= 3 4 times 3 =12 12 divide3 =4

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.012 divided by 3 ??? Are you sure in denominator it is 3 ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im not too good with my unit circle

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Dear, what will you get when you will square 3 ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Check the colored things here : \[\frac{2 \sqrt{3}}{\color{red}{3}} \times \frac{2 \sqrt{3}}{\color{red}{3}} = ??\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes it is 12 divided by 9 and not 3.. So what will you get now ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i was thinking addition

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0my mistake...srry if i took up yhur time

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It is okay but be careful from next time... These are called "Silly Mistakes..." Ok, now concentrate more on new problems...
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