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Have you differentiated F(x) and then sub'ed \(\frac{\pi}{6}\) into it?

Do you know the derivative of tan(x) ??

i kno the differvative is secxtanx
but i dont know where to go frm there :/

Yes, than just replace x by pi/6..

(2\[\sqrt{3}\]/3 and \[\sqrt{3}\]/3

\[F'(\frac{\pi}{6}) = \sec(\frac{\pi}{6}) \cdot \tan(\frac{\pi}{6})\]

igot tht part

What is the value of :
\[\sec (\frac{\pi}{6})\]

2root3/3

Yes and what is for tan(pi/6) = ??

root3/3

Wait, derivative of tan(x) isn't it sec^2(x) ??

its not ?

\[\frac{d}{dx} \tan(x) = \sec^2(x)\]

thts y im getting the wrong answer

thank you

You were doing the derivative of sec(x)..

yea

ok idk how to combine the 2 radicals

Where ??

sec^2

\[F'(\frac{\pi}{6}) = \sec^2(\frac{\pi}{6})\]

yea

|dw:1352970940060:dw|

\[\implies \frac{2 \sqrt{3}}{3} \times \frac{2\sqrt{3}}{3} \implies ??\]

This is simple multiplication and division now...

i know but im not getting the right answer

What are you getting tell me first...

Its not 4...
You are missing something.

\[\sqrt{3} \times \sqrt{3} = ??\]

2 times 2=4
root3 times root 3= 3
4 times 3 =12
12 divide3 =4

12 divided by 3 ???
Are you sure in denominator it is 3 ??

im not too good with my unit circle

Dear, what will you get when you will square 3 ??

Yes it is 12 divided by 9 and not 3..
So what will you get now ??

ohhhhhh

4/3

i was thinking addition

my mistake...srry if i took up yhur time

It is okay..

thanks a lot :)))