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Circuit analysis - my answers seem to deviate from those given.

Linear Algebra
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The answers are i1=1.180A,i2=-1.240A,i3=-0.058A,i4=-0.529A, and i5=0.471A.
I setup a system of linear equations using mesh analysis, for i1,i3,and i5, renaming them respectively as i_a,i_b,and i_c. the system I came up with is 6i_a+4(i_a-i_b)=12 2(i_b-i_c)+4(i_b-i_a)=6 2(i_c-i_b)+2i_c=2 or 10i_a-4i_b=12 -2i_a+6i_b-2i_c=6 -2i_b+4i_c=2 but this comes out to i_a=44/21, i_b=47/21, and i_c=34/21

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I got same answers as you..."inkyvoyd"
someone gave me answer, @jobs

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