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suneja

  • 3 years ago

solve the 4 degree equation x^4 - 2x^3 + 4x^2 + 8x - 21 =0, given that 2 of its roots are equal in magnitude but opposite in sign.????

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  1. shubhamsrg
    • 3 years ago
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    let roots be a,-a,b,c we have a-a +b+c = b+c =2 also, abc -abc -a^2 b - a^2c = -a^2(b+c) = 4 you can solve for a from here..seems it will be an imaginary root.. now you have 2 roots i.e. a and -a ..should be able to solve for other 2..

  2. shubhamsrg
    • 3 years ago
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    correction : abc -abc -a^2 b - a^2c = -a^2(b+c) = -8 *

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