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solve the 4 degree equation
x^4  2x^3 + 4x^2 + 8x  21 =0, given that 2 of its roots are equal in magnitude but opposite in sign.????
 one year ago
 one year ago
solve the 4 degree equation x^4  2x^3 + 4x^2 + 8x  21 =0, given that 2 of its roots are equal in magnitude but opposite in sign.????
 one year ago
 one year ago

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shubhamsrgBest ResponseYou've already chosen the best response.0
let roots be a,a,b,c we have aa +b+c = b+c =2 also, abc abc a^2 b  a^2c = a^2(b+c) = 4 you can solve for a from here..seems it will be an imaginary root.. now you have 2 roots i.e. a and a ..should be able to solve for other 2..
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
correction : abc abc a^2 b  a^2c = a^2(b+c) = 8 *
 one year ago
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