## bbillingsley3 3 years ago For number 2, am I doing this correct? J^b = [Ad(g4g3g2)^-1 * {0;0;1} , Ad(g4g3)^-1*{0;0;1} , Ad(g4)^-1 * {0;0;1}] J^b = [ (g4g3g2)^-1 * {0;0;1} * g4g3g2 , (g4g3)^-1 *{0;0;1} * g4g3 , g4^-1 * {0;0;1} * g4]

1. Chipper10

The first part looks right but the second part does not. At the end of the homework there is a formula for the matrix form of the adjoint. you need to multiply that by the [0;0;1]s and THEN invert

2. bbillingsley3

I thought that was what I did. For example: I multiplied (g4g3g2)^-1 * {0;0;1} * g4g3g2 g4g3g2 is the inverser of (g4g3g2)^-1

3. bbillingsley3

O nevermind, I think I understand now. I need to multiply J*d for (g4g3g2), right?

4. Chipper10

5. Chipper10

You want to do the latter

6. bbillingsley3

How would I calculate Js? Would it be: Js = Ad(ge) * Jb ?

7. Chipper10

Yep

8. bbillingsley3

9. Chipper10

I assume you're referring to the 2D case. The formula for the matrix form of the adjoint is given at the end of the homework.

10. Jaynator495

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