Here's the question you clicked on:
bbillingsley3
For number 2, am I doing this correct? J^b = [Ad(g4g3g2)^-1 * {0;0;1} , Ad(g4g3)^-1*{0;0;1} , Ad(g4)^-1 * {0;0;1}] J^b = [ (g4g3g2)^-1 * {0;0;1} * g4g3g2 , (g4g3)^-1 *{0;0;1} * g4g3 , g4^-1 * {0;0;1} * g4]
The first part looks right but the second part does not. At the end of the homework there is a formula for the matrix form of the adjoint. you need to multiply that by the [0;0;1]s and THEN invert
I thought that was what I did. For example: I multiplied (g4g3g2)^-1 * {0;0;1} * g4g3g2 g4g3g2 is the inverser of (g4g3g2)^-1
O nevermind, I think I understand now. I need to multiply J*d for (g4g3g2), right?
\[Ad_{h^{-1}}(g) \neq (Ad_h(g))^{-1}\]
You want to do the latter
How would I calculate Js? Would it be: Js = Ad(ge) * Jb ?
Does Ad(ge) = [Ad(g4g3g2g1)^-1*{0;0;1} * (g4g3g2g1)] ?
I assume you're referring to the 2D case. The formula for the matrix form of the adjoint is given at the end of the homework.
Welcome To OpenStudy! Here you will find great helpers and friends, a community of students that help students! We hope you enjoy the experience!