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bbillingsley3
 3 years ago
For number 2, am I doing this correct?
J^b = [Ad(g4g3g2)^1 * {0;0;1} , Ad(g4g3)^1*{0;0;1} , Ad(g4)^1 * {0;0;1}]
J^b = [ (g4g3g2)^1 * {0;0;1} * g4g3g2 , (g4g3)^1 *{0;0;1} * g4g3 , g4^1 * {0;0;1} * g4]
bbillingsley3
 3 years ago
For number 2, am I doing this correct? J^b = [Ad(g4g3g2)^1 * {0;0;1} , Ad(g4g3)^1*{0;0;1} , Ad(g4)^1 * {0;0;1}] J^b = [ (g4g3g2)^1 * {0;0;1} * g4g3g2 , (g4g3)^1 *{0;0;1} * g4g3 , g4^1 * {0;0;1} * g4]

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Chipper10
 3 years ago
Best ResponseYou've already chosen the best response.0The first part looks right but the second part does not. At the end of the homework there is a formula for the matrix form of the adjoint. you need to multiply that by the [0;0;1]s and THEN invert

bbillingsley3
 3 years ago
Best ResponseYou've already chosen the best response.0I thought that was what I did. For example: I multiplied (g4g3g2)^1 * {0;0;1} * g4g3g2 g4g3g2 is the inverser of (g4g3g2)^1

bbillingsley3
 3 years ago
Best ResponseYou've already chosen the best response.0O nevermind, I think I understand now. I need to multiply J*d for (g4g3g2), right?

Chipper10
 3 years ago
Best ResponseYou've already chosen the best response.0\[Ad_{h^{1}}(g) \neq (Ad_h(g))^{1}\]

Chipper10
 3 years ago
Best ResponseYou've already chosen the best response.0You want to do the latter

bbillingsley3
 3 years ago
Best ResponseYou've already chosen the best response.0How would I calculate Js? Would it be: Js = Ad(ge) * Jb ?

bbillingsley3
 3 years ago
Best ResponseYou've already chosen the best response.0Does Ad(ge) = [Ad(g4g3g2g1)^1*{0;0;1} * (g4g3g2g1)] ?

Chipper10
 3 years ago
Best ResponseYou've already chosen the best response.0I assume you're referring to the 2D case. The formula for the matrix form of the adjoint is given at the end of the homework.

Jaynator495
 2 months ago
Best ResponseYou've already chosen the best response.0Welcome To OpenStudy! Here you will find great helpers and friends, a community of students that help students! We hope you enjoy the experience!
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