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bbillingsley3

  • 2 years ago

For number 2, am I doing this correct? J^b = [Ad(g4g3g2)^-1 * {0;0;1} , Ad(g4g3)^-1*{0;0;1} , Ad(g4)^-1 * {0;0;1}] J^b = [ (g4g3g2)^-1 * {0;0;1} * g4g3g2 , (g4g3)^-1 *{0;0;1} * g4g3 , g4^-1 * {0;0;1} * g4]

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  1. Chipper10
    • 2 years ago
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    The first part looks right but the second part does not. At the end of the homework there is a formula for the matrix form of the adjoint. you need to multiply that by the [0;0;1]s and THEN invert

  2. bbillingsley3
    • 2 years ago
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    I thought that was what I did. For example: I multiplied (g4g3g2)^-1 * {0;0;1} * g4g3g2 g4g3g2 is the inverser of (g4g3g2)^-1

  3. bbillingsley3
    • 2 years ago
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    O nevermind, I think I understand now. I need to multiply J*d for (g4g3g2), right?

  4. Chipper10
    • 2 years ago
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    \[Ad_{h^{-1}}(g) \neq (Ad_h(g))^{-1}\]

  5. Chipper10
    • 2 years ago
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    You want to do the latter

  6. bbillingsley3
    • 2 years ago
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    How would I calculate Js? Would it be: Js = Ad(ge) * Jb ?

  7. Chipper10
    • 2 years ago
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    Yep

  8. bbillingsley3
    • 2 years ago
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    Does Ad(ge) = [Ad(g4g3g2g1)^-1*{0;0;1} * (g4g3g2g1)] ?

  9. Chipper10
    • 2 years ago
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    I assume you're referring to the 2D case. The formula for the matrix form of the adjoint is given at the end of the homework.

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