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bbillingsley3 Group Title

For number 2, am I doing this correct? J^b = [Ad(g4g3g2)^-1 * {0;0;1} , Ad(g4g3)^-1*{0;0;1} , Ad(g4)^-1 * {0;0;1}] J^b = [ (g4g3g2)^-1 * {0;0;1} * g4g3g2 , (g4g3)^-1 *{0;0;1} * g4g3 , g4^-1 * {0;0;1} * g4]

  • 2 years ago
  • 2 years ago

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  1. Chipper10 Group Title
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    The first part looks right but the second part does not. At the end of the homework there is a formula for the matrix form of the adjoint. you need to multiply that by the [0;0;1]s and THEN invert

    • 2 years ago
  2. bbillingsley3 Group Title
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    I thought that was what I did. For example: I multiplied (g4g3g2)^-1 * {0;0;1} * g4g3g2 g4g3g2 is the inverser of (g4g3g2)^-1

    • 2 years ago
  3. bbillingsley3 Group Title
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    O nevermind, I think I understand now. I need to multiply J*d for (g4g3g2), right?

    • 2 years ago
  4. Chipper10 Group Title
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    \[Ad_{h^{-1}}(g) \neq (Ad_h(g))^{-1}\]

    • 2 years ago
  5. Chipper10 Group Title
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    You want to do the latter

    • 2 years ago
  6. bbillingsley3 Group Title
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    How would I calculate Js? Would it be: Js = Ad(ge) * Jb ?

    • 2 years ago
  7. Chipper10 Group Title
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    Yep

    • 2 years ago
  8. bbillingsley3 Group Title
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    Does Ad(ge) = [Ad(g4g3g2g1)^-1*{0;0;1} * (g4g3g2g1)] ?

    • 2 years ago
  9. Chipper10 Group Title
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    I assume you're referring to the 2D case. The formula for the matrix form of the adjoint is given at the end of the homework.

    • 2 years ago
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