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toxicdevil
Group Title
With what muzzle speed must a projectile be fired vertically from a
gun on the surface of the Earth if it is to (barely) reach the distance of
the Moon?
Neglect the gravity of the Moon, neglect atmospheric friction, and neglect
the rotational velocity of the Earth in the following problem.
I am totally clueless as to how to approach the problem. i tried GMm/r=1/2mv^2 but the answer is not correct.
 one year ago
 one year ago
toxicdevil Group Title
With what muzzle speed must a projectile be fired vertically from a gun on the surface of the Earth if it is to (barely) reach the distance of the Moon? Neglect the gravity of the Moon, neglect atmospheric friction, and neglect the rotational velocity of the Earth in the following problem. I am totally clueless as to how to approach the problem. i tried GMm/r=1/2mv^2 but the answer is not correct.
 one year ago
 one year ago

This Question is Closed

JFraser Group TitleBest ResponseYou've already chosen the best response.0
you need to use the kinematic equations to find the speed necessary to lift a bullet so that it "just" makes it to the moon before falling back down again. try using\[\Delta x = v_0 *t + \frac{1}{2} g*t^2\]\[(v_f)^2 = (v_0)^2 + 2a \Delta x\] and\or \[\Delta x = \frac{1}{2} (v_0 + v_f)*t\] I'd start with the second one, if I were you.
 one year ago

toxicdevil Group TitleBest ResponseYou've already chosen the best response.0
@JFraser How can I use equations of motion when the value of g is not constant.
 one year ago

JFraser Group TitleBest ResponseYou've already chosen the best response.0
assume that it is
 one year ago

toxicdevil Group TitleBest ResponseYou've already chosen the best response.0
Wrong. I used Initial P.E + Initial K.E=Final K.E(which is zero) + Final P.E. Now the answer matches the back of the book.
 one year ago
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