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use elimination method
add down using elimination method
add solve for x then solve for y I think it will be easier
multiply both side of x+y=4 by 5 and multiply both side of 2x-y=5 by 4
I think adding two equation will give you in x terms only... no ned to go in a roundabout way
welcome..so u got it... O glad..
Is the answer suppose to be a decimal tho??
because i got -0.3333333333.. etc.
what did u get it??
show in -1/3
yes... first you nd to eliminate one variable... sinc there are two equations and two unknowns.. it would is possible... but you won't get -0.3333.. in this case
NO!!! you have two use the equations which are available to you
Try using substitution and see if you got the same as me. (:
Oh okay now I see.
jazzy missed one y there
I prefer substitution. x + y = 4 2x - y = 5 Solve for x in the first equation. x + y = 4 Subtract y. x = 4 - y Substitute the value of x into the second equation. Solve for y. 2(4 - y) - y = 5 Distribute. 8 - 2y - y= 5 Subtract 8. -2y - y = -3 -3y = -3 Divide both sides by -3. y = 1 Now plug in the value of y(1) into any equation to solve for x. x + y = 4 x + 1 = 4 Subtract 1 x = 3 ---------------------------------- So x = 3 and y = 1
2(4 - y) - y= 5 8 - 3y = 5
2(4 - y) - y= 5 8 - 3y = 5
Thank you catching that mistake! (:
It should be right now!
yes you got it jazzy.. but a very simpl method is there
sice answer is already wrote here( which I don't like to do write directly) it is for you to know that there is a simple method than this
actually it is derivd from the method mentioned here.. It is actually a special case of this method.. it is applicabl here since in one equation +y and in other equation -y is there actually the problem is simple x+y=4 2x-y=5 |dw:1353003234368:dw| so when we add both equation (LHS with LHS and RHS with RHS) you get 3x =9 which can be simplified quickly and reach the answer fast
actually the problem is simple x+y=4 2x-y=5 add x+y+2x-y = 5+4 3x+0 = 9 3x =9 if you substitute the value of x in equn 1 you get th value of y....
Welcome...But remember it is a special case ;) all the best
Ha ha okay, thank youagain !:p