Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

hba

  • 3 years ago

Question about functions :

  • This Question is Closed
  1. Fox375
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    whats the question?

  2. hba
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Which of the following expresses the domain of \[g(x)=\frac{ 3 }{ (x-2)(x+3) }\] A)\[\left\{ x:x \neq 0 \right\}\] B)\[\left\{ x:x \neq 2 \right\}\] C)\[\left\{ x:x \neq -3 \right\}\]

  3. hba
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @rajathsbhat

  4. hba
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @waterineyes ?

  5. waterineyes
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Firstly, denominator must not be 0..

  6. waterineyes
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    \[(x-2)(x+3) \ne 0\] Find x..

  7. hba
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So x=2,x=-3

  8. waterineyes
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    This will have two correct choices... Not equal to man not equal to.. \(x \ne 2\) and \(x \ne -3\)

  9. hba
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yeah right ,What next @waterineyes

  10. hba
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so b and c cannot be the answer :)

  11. waterineyes
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Cannot?? Why??

  12. hba
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I mean can be the answer.

  13. waterineyes
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Yes but both...

  14. hba
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    {x:x is not equal to 2 and x:x is not equal to 3} got it thanks :)

  15. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy