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hba

  • 2 years ago

Question about functions :

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  1. Fox375
    • 2 years ago
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    whats the question?

  2. hba
    • 2 years ago
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    Which of the following expresses the domain of \[g(x)=\frac{ 3 }{ (x-2)(x+3) }\] A)\[\left\{ x:x \neq 0 \right\}\] B)\[\left\{ x:x \neq 2 \right\}\] C)\[\left\{ x:x \neq -3 \right\}\]

  3. hba
    • 2 years ago
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    @rajathsbhat

  4. hba
    • 2 years ago
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    @waterineyes ?

  5. waterineyes
    • 2 years ago
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    Firstly, denominator must not be 0..

  6. waterineyes
    • 2 years ago
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    \[(x-2)(x+3) \ne 0\] Find x..

  7. hba
    • 2 years ago
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    So x=2,x=-3

  8. waterineyes
    • 2 years ago
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    This will have two correct choices... Not equal to man not equal to.. \(x \ne 2\) and \(x \ne -3\)

  9. hba
    • 2 years ago
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    Yeah right ,What next @waterineyes

  10. hba
    • 2 years ago
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    so b and c cannot be the answer :)

  11. waterineyes
    • 2 years ago
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    Cannot?? Why??

  12. hba
    • 2 years ago
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    I mean can be the answer.

  13. waterineyes
    • 2 years ago
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    Yes but both...

  14. hba
    • 2 years ago
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    {x:x is not equal to 2 and x:x is not equal to 3} got it thanks :)

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