## Stormegeddon 3 years ago Geometry Proof. Please HELP!!!! (Prove in six steps) Given: AD is a straight line, and AE = DB, AC = DF, <A = <D Prove: <C = <F

1. Stormegeddon

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2. jazy

@stormegddon I don't know how to write it. The only way I could think of proving this is: You can prove <C = <F using the SAS theorem for triangles. SAS = Side-Angle-Side theorem. You know that side AE = DB, angle A = angle D, and side AC = DF. Therefor the two triangles are congruent, so all their angles and sides are the same.

3. Stormegeddon

The way we have our proofs set up is like a T box. 1 side has statements and then the other side has the reasons for those statements.

4. Stormegeddon

Now I don't understand this proof but this was the example in the book. Proof Statements: (< = Angle) 1) Triangles ABC and DEF with <A = <D, AB = DE, <B = <E 2) Place triangle ABC and triangle DEF so that A coincides with D and AB falls along DE 3.) Point B must coincide with point E 4) AC must fall along DF and BC must fall along EF 5) Point C must coincide with Point F 6) AC = DF 7) Triangle ABC is congruent to triangle DEF PROOF REASONS: 1) Given 2) A geometric figure may be freely moved in space without any change in its form or size (Postulate 5) 3) Definition of equal line segments 4) Def. of equal angles 5) Two lines can intersect at but one point 6) Def. of equal line segments 7) S.A.S. (Theorem 1)

5. Stormegeddon

could you give a list of statements and reasons? I am really confused

6. jasmynarteaga1

jazy is right just say that triangle ABC is congruent to triangle DEF by Side Angle Side and then say angle C is congruent to angle F by CPCTC.

7. Stormegeddon

I need a six step proof though. Some stupid hw assignment it has to be 6 steps. I have 3 of them from what you gave me but what are steps 4, 5, and 6 STATEMENTS: 1) AD is a straight line, and AE = DB, AC = DF, <A = <D 2) 3) 4) 5) triangle ABC is congruent to triangle DEF 6) angle C is congruent to angle F REASONS: 1) Given 2) 3) 4) 5) SAS 6) CPCTE