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we can equate vertex with vertex then; a=p b=q c=r for starters
since b=q, and they give you eqaustions for b and q; then write the equations equal to each other and it should be a simple matter to solve for v
yeah but Im not sure how to do that
what is the equation for b?
what is the equation for q? since b = q then its also true that: (equation for b) = (equation for q)
good, and can you finish the setup? ill help you thru it once i see that you can at least set it up
8v-9 is Q
good, then (equation for b) = (equation for q) 5v+6 = 8v-9
so then do you subtract 5 from both sides?
close, there is a v stuck to the 5, so lets subtract 5v from each side for starters
5v+6 = 8v-9 -5v -5v ---------------- 6 = 3v - 9 what do you think another good move would be?
add 9 to both sides?
correct 6 = 3v - 9 +9 +9 ----------- 15 = 3v only one more move left, what do you think we should do?
divide 3 on both sides to get v
excellent 15/3 = 3v/3 5 = v so now that we know a normal looking value for v, we can use it to find the values of b and q right?
then what is our solution :)
Like plug 5 into the original problem?
yes, and it should work in either equation for b or for q and give us the same value
it looks like you might have blended the 2 equations into an abomination of desolation :) b = 5v+6 = 5(5)+6 q = 8v-9 =8(5)-9
so 16 and 31? I feel like thats totally off
b = 5v+6 = 5(5)+6 = 25 + 6 = 31 q = 8v-9 =8(5)-9 = 40 - 9 = 31 b = q = 31
OH haha DUH sorry I got it now!
;) good luck