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lornbeach Group Title

Simplify the given expression:

  • 2 years ago
  • 2 years ago

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  1. lornbeach Group Title
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    • 2 years ago
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  2. maym0Re97 Group Title
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    i7/1+9i

    • 2 years ago
  3. lornbeach Group Title
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    thats not an answer choice

    • 2 years ago
  4. maym0Re97 Group Title
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    What are the choices?

    • 2 years ago
  5. lornbeach Group Title
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    7+7i/2 63+7i/82 -7+7i/2 -63+7i/82

    • 2 years ago
  6. Hero Group Title
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    \[ \sqrt{-49} = \sqrt{49 \dot\ -1} = \sqrt{49} \sqrt{-1} = 7i \\(3 + 4i) - (2 - 5i) = (3 - 2) + (4i + 5i) = 1 + 9i \]

    • 2 years ago
  7. Hero Group Title
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    I have to agree with @maym0Re97

    • 2 years ago
  8. maym0Re97 Group Title
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    Lol that's what I got, but it's not an answer choice

    • 2 years ago
  9. lornbeach Group Title
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    i got that answer as well, but it isnt a choice

    • 2 years ago
  10. Hero Group Title
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    There's probably an equivalent choice

    • 2 years ago
  11. Hero Group Title
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    Multiply top and bottom by 1 - 9i and see what happens

    • 2 years ago
  12. lornbeach Group Title
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    would it be 63+7i/82?

    • 2 years ago
  13. satellite73 Group Title
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    your job is to rewrite in standard form as \(a+bi\) which means do what @hero said

    • 2 years ago
  14. satellite73 Group Title
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    \[\frac{7i}{1+9i}\times \frac{1-9i}{1-9i}\] the denominator is \(1^2+9^2=82\) all the work is in the numerator

    • 2 years ago
  15. satellite73 Group Title
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    yes you have it

    • 2 years ago
  16. lornbeach Group Title
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    thank you(:

    • 2 years ago
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