A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Simplify the given expression:
anonymous
 3 years ago
Simplify the given expression:

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thats not an answer choice

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What are the choices?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.07+7i/2 63+7i/82 7+7i/2 63+7i/82

Hero
 3 years ago
Best ResponseYou've already chosen the best response.0\[ \sqrt{49} = \sqrt{49 \dot\ 1} = \sqrt{49} \sqrt{1} = 7i \\(3 + 4i)  (2  5i) = (3  2) + (4i + 5i) = 1 + 9i \]

Hero
 3 years ago
Best ResponseYou've already chosen the best response.0I have to agree with @maym0Re97

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Lol that's what I got, but it's not an answer choice

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i got that answer as well, but it isnt a choice

Hero
 3 years ago
Best ResponseYou've already chosen the best response.0There's probably an equivalent choice

Hero
 3 years ago
Best ResponseYou've already chosen the best response.0Multiply top and bottom by 1  9i and see what happens

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0would it be 63+7i/82?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0your job is to rewrite in standard form as \(a+bi\) which means do what @hero said

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{7i}{1+9i}\times \frac{19i}{19i}\] the denominator is \(1^2+9^2=82\) all the work is in the numerator
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.