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lornbeach

  • 3 years ago

Simplify the given expression:

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  1. lornbeach
    • 3 years ago
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  2. maym0Re97
    • 3 years ago
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    i7/1+9i

  3. lornbeach
    • 3 years ago
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    thats not an answer choice

  4. maym0Re97
    • 3 years ago
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    What are the choices?

  5. lornbeach
    • 3 years ago
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    7+7i/2 63+7i/82 -7+7i/2 -63+7i/82

  6. Hero
    • 3 years ago
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    \[ \sqrt{-49} = \sqrt{49 \dot\ -1} = \sqrt{49} \sqrt{-1} = 7i \\(3 + 4i) - (2 - 5i) = (3 - 2) + (4i + 5i) = 1 + 9i \]

  7. Hero
    • 3 years ago
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    I have to agree with @maym0Re97

  8. maym0Re97
    • 3 years ago
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    Lol that's what I got, but it's not an answer choice

  9. lornbeach
    • 3 years ago
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    i got that answer as well, but it isnt a choice

  10. Hero
    • 3 years ago
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    There's probably an equivalent choice

  11. Hero
    • 3 years ago
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    Multiply top and bottom by 1 - 9i and see what happens

  12. lornbeach
    • 3 years ago
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    would it be 63+7i/82?

  13. anonymous
    • 3 years ago
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    your job is to rewrite in standard form as \(a+bi\) which means do what @hero said

  14. anonymous
    • 3 years ago
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    \[\frac{7i}{1+9i}\times \frac{1-9i}{1-9i}\] the denominator is \(1^2+9^2=82\) all the work is in the numerator

  15. anonymous
    • 3 years ago
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    yes you have it

  16. lornbeach
    • 3 years ago
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    thank you(:

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