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cocopuffshead
 2 years ago
Best ResponseYou've already chosen the best response.0easy best response

LolWolf
 2 years ago
Best ResponseYou've already chosen the best response.11+1=2, if \(1, 2\in \mathbb{Z}\), otherwise, we can have \(1+1=0\), if in \(\mathbb{Z}/2\mathbb{Z}\) along with other interesting rings and groups.

cocopuffshead
 2 years ago
Best ResponseYou've already chosen the best response.0and i spelled that worng

jasonxx
 2 years ago
Best ResponseYou've already chosen the best response.1these are the three posibilities 0,1,2 ...............1+1 could be any of these

Studentc14
 2 years ago
Best ResponseYou've already chosen the best response.01+1=2 because the world says so. Don't try to overthink it! This is one problem that no one should even have to think about, lol
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