A community for students. Sign up today!
Here's the question you clicked on:
← 55 members online
 0 viewing

This Question is Closed

cocopuffshead
 2 years ago
Best ResponseYou've already chosen the best response.0easy best response

LolWolf
 2 years ago
Best ResponseYou've already chosen the best response.11+1=2, if \(1, 2\in \mathbb{Z}\), otherwise, we can have \(1+1=0\), if in \(\mathbb{Z}/2\mathbb{Z}\) along with other interesting rings and groups.

cocopuffshead
 2 years ago
Best ResponseYou've already chosen the best response.0and i spelled that worng

jasonxx
 2 years ago
Best ResponseYou've already chosen the best response.1these are the three posibilities 0,1,2 ...............1+1 could be any of these

Studentc14
 2 years ago
Best ResponseYou've already chosen the best response.01+1=2 because the world says so. Don't try to overthink it! This is one problem that no one should even have to think about, lol
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.