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ZeroAT
Group Title
Write an equation for the tangent line to f(x) = 4x + 3/x at x = 1
How do i solve this?
 one year ago
 one year ago
ZeroAT Group Title
Write an equation for the tangent line to f(x) = 4x + 3/x at x = 1 How do i solve this?
 one year ago
 one year ago

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LolWolf Group TitleBest ResponseYou've already chosen the best response.0
So, we need to know the slope at this point, this is given by: \[ \frac{d}{dx}\left(4x+\frac{3}{x}\right)=4\frac{3}{x^2} \]Evaluating this at \(x=1\): \[ 4\frac{3}{x^2}\Bigg_{x=1}=4+3=1 \]So the slope of the line is 1 at this point. Now, find a point on the line: \[ 4(1)+\frac{3}{1}=7=y \]Which means: \[ y+7=1(x+1) \]Et voilá.
 one year ago

ZeroAT Group TitleBest ResponseYou've already chosen the best response.0
Which would be the correct answer: A) 7x + y = 6 B) 6x + 2y = 5 C) 7x + y = 6 D) 6x + 2y = 5
 one year ago

LolWolf Group TitleBest ResponseYou've already chosen the best response.0
Wait, I screwed up, it's: \[ 4\frac{3}{x^2}\Bigg_{x=1}=43=7 \]So: \[ y+7=7(x+1) \]
 one year ago

ZeroAT Group TitleBest ResponseYou've already chosen the best response.0
oh! that explains why i coudnt get the answer. Thanks for the assistance
 one year ago

LolWolf Group TitleBest ResponseYou've already chosen the best response.0
Sure thing
 one year ago

ZeroAT Group TitleBest ResponseYou've already chosen the best response.0
One more question..How would i get the end results in one of those 4 possible results i mentioned? can you show me?
 one year ago

LolWolf Group TitleBest ResponseYou've already chosen the best response.0
Just solve for the same form, it's roughly the same case.
 one year ago
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