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anonymous
 3 years ago
Write an equation for the tangent line to f(x) = 4x + 3/x at x = 1
How do i solve this?
anonymous
 3 years ago
Write an equation for the tangent line to f(x) = 4x + 3/x at x = 1 How do i solve this?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So, we need to know the slope at this point, this is given by: \[ \frac{d}{dx}\left(4x+\frac{3}{x}\right)=4\frac{3}{x^2} \]Evaluating this at \(x=1\): \[ 4\frac{3}{x^2}\Bigg_{x=1}=4+3=1 \]So the slope of the line is 1 at this point. Now, find a point on the line: \[ 4(1)+\frac{3}{1}=7=y \]Which means: \[ y+7=1(x+1) \]Et voilá.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Which would be the correct answer: A) 7x + y = 6 B) 6x + 2y = 5 C) 7x + y = 6 D) 6x + 2y = 5

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Wait, I screwed up, it's: \[ 4\frac{3}{x^2}\Bigg_{x=1}=43=7 \]So: \[ y+7=7(x+1) \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh! that explains why i coudnt get the answer. Thanks for the assistance

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0One more question..How would i get the end results in one of those 4 possible results i mentioned? can you show me?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Just solve for the same form, it's roughly the same case.
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