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ZeroAT
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Write an equation for the tangent line to f(x) = 4x + 3/x at x = 1
How do i solve this?
 2 years ago
 2 years ago
ZeroAT Group Title
Write an equation for the tangent line to f(x) = 4x + 3/x at x = 1 How do i solve this?
 2 years ago
 2 years ago

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LolWolf Group TitleBest ResponseYou've already chosen the best response.0
So, we need to know the slope at this point, this is given by: \[ \frac{d}{dx}\left(4x+\frac{3}{x}\right)=4\frac{3}{x^2} \]Evaluating this at \(x=1\): \[ 4\frac{3}{x^2}\Bigg_{x=1}=4+3=1 \]So the slope of the line is 1 at this point. Now, find a point on the line: \[ 4(1)+\frac{3}{1}=7=y \]Which means: \[ y+7=1(x+1) \]Et voilá.
 2 years ago

ZeroAT Group TitleBest ResponseYou've already chosen the best response.0
Which would be the correct answer: A) 7x + y = 6 B) 6x + 2y = 5 C) 7x + y = 6 D) 6x + 2y = 5
 2 years ago

LolWolf Group TitleBest ResponseYou've already chosen the best response.0
Wait, I screwed up, it's: \[ 4\frac{3}{x^2}\Bigg_{x=1}=43=7 \]So: \[ y+7=7(x+1) \]
 2 years ago

ZeroAT Group TitleBest ResponseYou've already chosen the best response.0
oh! that explains why i coudnt get the answer. Thanks for the assistance
 2 years ago

ZeroAT Group TitleBest ResponseYou've already chosen the best response.0
One more question..How would i get the end results in one of those 4 possible results i mentioned? can you show me?
 2 years ago

LolWolf Group TitleBest ResponseYou've already chosen the best response.0
Just solve for the same form, it's roughly the same case.
 2 years ago
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