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missbempz

  • 2 years ago

How do you factor 5ab-2b squared-2b+5a?

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  1. lgbasallote
    • 2 years ago
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    try rearranging them \[\implies 5ab + 5a - 2b^2 - 2b\] do you see how to factor it now? or no?

  2. missbempz
    • 2 years ago
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    No... Like I want to be taught the process to fully factor it

  3. lgbasallote
    • 2 years ago
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    well the first step is to rearrange it (like i did)

  4. lgbasallote
    • 2 years ago
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    the next step...is to group the terms like this \[\implies (5ab + 5a) + (-2b^2 - 2b)\] still don't see the factor?

  5. missbempz
    • 2 years ago
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    Yeah I see it .. So when you rearrange it... you do it according to the numbers and letters right?

  6. lgbasallote
    • 2 years ago
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    yes

  7. lgbasallote
    • 2 years ago
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    because you want the common terms to be together

  8. missbempz
    • 2 years ago
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    Oh okay, so for instance, if it said 6ab+6a, I would group that first? Does it matter which order it's in?

  9. lgbasallote
    • 2 years ago
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    it depends... remember: in addition there is a commutative property...that means order doesn't matter... but in subtraction...there's no commutative property

  10. lgbasallote
    • 2 years ago
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    unless you do it like this 6ab - 6a => -6a + 6ab that's fine.. but these are not equal 6ab - 6a => 6a - 6ab

  11. missbempz
    • 2 years ago
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    Oh okay, so what would you do if it was in subtraction? Can you give me another question to solve to see if I understand?

  12. lgbasallote
    • 2 years ago
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    sure try this \[\huge 5xy + 10y - 4x^2 + 8y^2\]

  13. lgbasallote
    • 2 years ago
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    it's a bit different since you don't have same numbers here

  14. lgbasallote
    • 2 years ago
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    sorry...i have to go now...

  15. missbempz
    • 2 years ago
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    Okay

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