At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
try rearranging them \[\implies 5ab + 5a - 2b^2 - 2b\] do you see how to factor it now? or no?
No... Like I want to be taught the process to fully factor it
well the first step is to rearrange it (like i did)
the next step...is to group the terms like this \[\implies (5ab + 5a) + (-2b^2 - 2b)\] still don't see the factor?
Yeah I see it .. So when you rearrange it... you do it according to the numbers and letters right?
because you want the common terms to be together
Oh okay, so for instance, if it said 6ab+6a, I would group that first? Does it matter which order it's in?
it depends... remember: in addition there is a commutative property...that means order doesn't matter... but in subtraction...there's no commutative property
unless you do it like this 6ab - 6a => -6a + 6ab that's fine.. but these are not equal 6ab - 6a => 6a - 6ab
Oh okay, so what would you do if it was in subtraction? Can you give me another question to solve to see if I understand?
sure try this \[\huge 5xy + 10y - 4x^2 + 8y^2\]
it's a bit different since you don't have same numbers here
sorry...i have to go now...