## missbempz 3 years ago How do you factor 5ab-2b squared-2b+5a?

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1. lgbasallote

try rearranging them \[\implies 5ab + 5a - 2b^2 - 2b\] do you see how to factor it now? or no?

2. missbempz

No... Like I want to be taught the process to fully factor it

3. lgbasallote

well the first step is to rearrange it (like i did)

4. lgbasallote

the next step...is to group the terms like this \[\implies (5ab + 5a) + (-2b^2 - 2b)\] still don't see the factor?

5. missbempz

Yeah I see it .. So when you rearrange it... you do it according to the numbers and letters right?

6. lgbasallote

yes

7. lgbasallote

because you want the common terms to be together

8. missbempz

Oh okay, so for instance, if it said 6ab+6a, I would group that first? Does it matter which order it's in?

9. lgbasallote

it depends... remember: in addition there is a commutative property...that means order doesn't matter... but in subtraction...there's no commutative property

10. lgbasallote

unless you do it like this 6ab - 6a => -6a + 6ab that's fine.. but these are not equal 6ab - 6a => 6a - 6ab

11. missbempz

Oh okay, so what would you do if it was in subtraction? Can you give me another question to solve to see if I understand?

12. lgbasallote

sure try this \[\huge 5xy + 10y - 4x^2 + 8y^2\]

13. lgbasallote

it's a bit different since you don't have same numbers here

14. lgbasallote

sorry...i have to go now...

15. missbempz

Okay