On the first example problem for session 32 (http://ocw.mit.edu/courses/mathematics/18-02sc-multivariable-calculus-fall-2010/part-b-chain-rule-gradient-and-directional-derivatives/session-32-total-differentials-and-the-chain-rule/MIT18_02SC_we_15_comb.pdf) why is the partial derivative of w with respect to x only 3x^2+y? Shouldn't the y and z coefficients remain for the 3x^2?

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On the first example problem for session 32 (http://ocw.mit.edu/courses/mathematics/18-02sc-multivariable-calculus-fall-2010/part-b-chain-rule-gradient-and-directional-derivatives/session-32-total-differentials-and-the-chain-rule/MIT18_02SC_we_15_comb.pdf) why is the partial derivative of w with respect to x only 3x^2+y? Shouldn't the y and z coefficients remain for the 3x^2?

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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you are right..looks like a typo
Definitely an error, not a typo. And the error is propagated throughout the rest of the solution, giving the wrong answer to the problem.
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it is written 3x^2 yz + y so it is right the error is that dw/dy = x^3 z+ y while it has to be x^3 z+ x
@senecajim ThnX for the hint dun know how I missed it :/

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