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anonymous
 3 years ago
On the first example problem for session 32 (
http://ocw.mit.edu/courses/mathematics/1802scmultivariablecalculusfall2010/partbchainrulegradientanddirectionalderivatives/session32totaldifferentialsandthechainrule/MIT18_02SC_we_15_comb.pdf)
why is the partial derivative of w with respect to x only 3x^2+y? Shouldn't the y and z coefficients remain for the 3x^2?
anonymous
 3 years ago
On the first example problem for session 32 ( http://ocw.mit.edu/courses/mathematics/1802scmultivariablecalculusfall2010/partbchainrulegradientanddirectionalderivatives/session32totaldifferentialsandthechainrule/MIT18_02SC_we_15_comb.pdf) why is the partial derivative of w with respect to x only 3x^2+y? Shouldn't the y and z coefficients remain for the 3x^2?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you are right..looks like a typo

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Definitely an error, not a typo. And the error is propagated throughout the rest of the solution, giving the wrong answer to the problem.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Page not found Sorry, the page you requested was not found. :(

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Avva  Remove the "close paren" from the end of the URL. Then it loads.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it is written 3x^2 yz + y so it is right the error is that dw/dy = x^3 z+ y while it has to be x^3 z+ x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@senecajim ThnX for the hint dun know how I missed it :/
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