anonymous
  • anonymous
Please Help... A robot travels at a speed of 1.35 m/sec at a direction of 45.0 degrees for 305 seconds. It then travels at a speed of 1.50 m/sec at a direction of 140.0 degrees for 852 seconds. What is the total displacement at the end of the second maneuver? First, give the y component of the first displacement vector calculated in the problem.
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1308.08m u can use the law of cosines c^2=a^2+b^2-2ab cos (c) where cos(c)=cos(85degree)
anonymous
  • anonymous
Is 1308.08 the y component or the total displacement?
anonymous
  • anonymous
the total

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Firstly, I'm assuming that the degrees are calculated from a absolute degree frame. i.e. North is 000, East is 090. If not, please tell. The first , y-component, can be calc'ed by this: \(S_y=u_y t + \frac{1}{2} a_y t^2\) Now, since \(u_y\) will be \(u sin 45^o\)
anonymous
  • anonymous
Then, a_y= 0, t=305, sub it all in to find the \(S_y\) which is the y displacement.
anonymous
  • anonymous
Do you need further help?

Looking for something else?

Not the answer you are looking for? Search for more explanations.