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baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
\[\lim_{x\to 0}\left(\frac{(1+x)^{\frac{1}{x}}}{e}\right)^{\frac{1}{x}}.\]
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
sorry, thats kind of hard to see.
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
\[\LARGE \lim_{x\to 0}\left(\frac{(1+x)^{\frac{1}{x}}}{e}\right)^{\frac{1}{x}}.\]
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.2
\[ \Large e = \lim_{n \rightarrow \infty}\left(1+\frac{1}{n}\right)^n \]When you reparameterize: \(x=1/n\) \[\Large e = \lim_{x \rightarrow 0}\left(1+x\right)^\frac{1}{x} \]
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.2
So it's a matter of settling that outer 1/x
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
I haven't learned 'reparameterize' yet, so I would assume I wouldn't have to use that... Supposed to use L'Hospital's rule
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.2
Okay, then you need to have an indeterminate form of \(\infty /\infty\) or \(0/0\)
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
right.
 one year ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.1
dw:1353045336700:dw
 one year ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.1
dw:1353045499277:dw
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
@mahmit2012 I am supposed to use L'Hospital's rule.
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.2
I can't read that bottom line.
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
"and in this case it is 1/sqrt(e)
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.2
No, of the previous picture
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
I don't know
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.2
Okay, let's start with bringing in the \(1/x\) to the numerator and denominator and figuring out if that is an indeterminate form.
 one year ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.1
dw:1353047217870:dw
 one year ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.1
dw:1353047297672:dw
 one year ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
@waterineyes can you help me understand this maybe?
 one year ago
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