hba

In the xy-plane,the graph of the function h is a line.If h(-1)=4 and h(5)=1,what is the value of h(0) ?

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Rosh007

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I think it will b helpful if you consider h as f(x)
that is H(-1)=4
means... when value of x is -1 ; y value (f(x)= is 4...
and soon.. construct the the line equation using two point form.. then find value for h(0)

hba

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(-1,4) and (5,1)

philo1234

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We can find 2 points from h(-1)=4 and h(5)=1

Rosh007

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yes.. you got it

Rosh007

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now construct line equation

hba

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What next ?

philo1234

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Use the points to find the slope

hba

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y-y1=m(x-x1) ??

Rosh007

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yes

hba

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m=y2-y1/x2-x1

Rosh007

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yes

hba

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m=-1/2

hba

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y+1=-1/2(x-4)

Rosh007

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??? what is x1 and y1

hba

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(x1,y1)=(-1,4)

Rosh007

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y+1=-1/2(x-4) is it y-y1=m(x-x1) ??? can you please check...

Rosh007

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your slope is correct...but the point you took is wrong

hba

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No it is correct :)

hba

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Do i have to take the other two points ?

Rosh007

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is it...I have doubt..
y1 is 4 and x1 is-1... but in the abopve equation you took y1 as -1 and x1 as 4
amI right?

hba

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My bad :(

Rosh007

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:) correct it

hba

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y-4=-1/2(x+1)

Rosh007

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yes.. now find h(0)

hba

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Ok so x=0

Rosh007

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yes

hba

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7/2=y < So 3.5 right ?

Rosh007

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yes.. good.. you got it

hba

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Thanks alot @Rosh007

Rosh007

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welcome hba