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nagdy1

  • 3 years ago

What is an equation for the line that passes through points (–1, –4) and (1, 4)? Write the equation in slope-intercept form. PLEASE SHOW STEP BY STEP

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  1. philo1234
    • 3 years ago
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    First find the slope using the 2 point can you do that?

  2. nagdy1
    • 3 years ago
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    yes

  3. philo1234
    • 3 years ago
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    What did you get?

  4. nagdy1
    • 3 years ago
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    zero slope or unidentified slop

  5. philo1234
    • 3 years ago
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    \[slope = \frac{ 4-(-4) }{ 1-(-1) }\]

  6. nagdy1
    • 3 years ago
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    that's all

  7. philo1234
    • 3 years ago
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    Nope you then need to use this slope and one of the points to find the equation. plug in this formula y-y1=m(x-x1) (x1,y1) is taken from one of the points

  8. nagdy1
    • 3 years ago
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    ok then what

  9. nagdy1
    • 3 years ago
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    i dont get my head is about to explode they gave me this question out of no where

  10. nagdy1
    • 3 years ago
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    can u show me step by step

  11. philo1234
    • 3 years ago
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    So what do you have so far? m (slope)=4, choose the point (1,4), x1=1, y1=4 you should have y-4=4(x-1)

  12. nagdy1
    • 3 years ago
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    can you please just put all the steps on one reply like: 1. 2. 3. 4.

  13. philo1234
    • 3 years ago
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    Step 1: Find the slope(m) = (4-(-4))/(1-(-1)) = 8/2=4

  14. nagdy1
    • 3 years ago
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    ok step 2

  15. philo1234
    • 3 years ago
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    Step 2: Use point slope form to get equation: y-y1=m(x-x1), m=4, point (1,4) where x1=1, y1=4 In the point-slope equation: y-1=4(x-4) Do u understand these step so far?

  16. nagdy1
    • 3 years ago
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    yes

  17. philo1234
    • 3 years ago
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    Step 3: Slope-intercept form is y=mx+b So we have y-1=4(x-4) Solve for y (that is put y by itself on one side).

  18. philo1234
    • 3 years ago
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    If you did that correctly you should get: y=4x-15

  19. nagdy1
    • 3 years ago
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    ohhh thanks man

  20. nagdy1
    • 3 years ago
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    ill give u a medal

  21. philo1234
    • 3 years ago
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    Sure no problem.

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