Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Help- find the limit of:

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
\[\lim_{x \rightarrow 2} \left( \frac{ 6 }{ x^2+2x-8 } \right)+\left(\frac{ x-6 }{ x^2-4} \right)\]
so I found that \[\lim_{x \rightarrow 2} \left( \frac{ 6 }{ (x+4)(x-2) } \right)+\left( \frac{ x-6 }{ (x+2)(x-2) } \right)\] Now what?????
now subsitute 2 in place of x

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

it will be 6/0. error. I can't do that yet.
1/0 = infinity
sorry 1/3. I see the next step in the book but I don't understand how they got to it. I will write it up.
\[\lim_{x \rightarrow 2}\left( \frac{ 6(x+2)+(x-6)(x+4) }{ (x+4)(x-2)(x+2) } \right)\]
they took the LCM in this step
ok. Can you explain that part to me? I don't seem to get it.
write all the terms in denominator if some term is repeating more then once , just write it one time. like in this case on one side u have (x+4)(x−2) and on other side (x+2)(x−2) so write them all in denominator but (x-2) is written twice so u will just write it one time
ok but what about the numerator? How did they get to that part?
ok now move back a step and see see what u had in denominator before . u had (x+4)(x−2) right?
so you compare the old denominator with new numerator whichever is the common denominator u cancel them and whatever is left u multiply it with numerator
|dw:1353067137453:dw|
|dw:1353067229340:dw|
|dw:1353067272848:dw|
|dw:1353067293846:dw|
are you getting what i am doing?
yes, so basically you devide the entire equation the the common denoiminator and then solve from there. I think I got it. Let me see if it works out.
\[\lim_{x \rightarrow 2} \left[\left( \frac{ 6 }{ (x+4)(x-2) } \right)+\left( \frac{ x-6 }{ (x+2)(x-2) } \right)\right]\] \[\lim_{x \rightarrow 2} \left[\frac{x+2}{x+2}\left( \frac{ 6 }{ (x+4)(x-2) } \right)+\frac{x+4}{x+4}\left( \frac{ x-6 }{ (x+2)(x-2) } \right)\right]\]
thnk

Not the answer you are looking for?

Search for more explanations.

Ask your own question