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mahmit2012 Group TitleBest ResponseYou've already chosen the best response.0
Is this equation or identity?
 2 years ago

logynklode Group TitleBest ResponseYou've already chosen the best response.0
Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side of the equation.
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
\(\cot x \sec^4 x = \cot x + 2 \tan x + \tan^3 x \)
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
its like above ?
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
*the equation u seeing in ur assessment sheet, is it like the one ive posted above ?
 2 years ago

logynklode Group TitleBest ResponseYou've already chosen the best response.0
its tan cubed x at the end other then that yes
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
ok thnks :) pick the side that has more terms, and do SOMETHING and try getting to the other side
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
here, the right side has more terms, right ?
 2 years ago

logynklode Group TitleBest ResponseYou've already chosen the best response.0
what? the irght side has more terms yeah
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
ya so we start with that side, and work, and prove that it equals left side.
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
\(\cot x + 2\tan x + \tan^3 x\) \(\frac{1}{\tan x} + 2\tan x + \tan^3 x\) \(\frac{1+ 2\tan^2 x + \tan^4 x}{\tan x}\) \(\frac{1+ \tan^2 x + \tan^2x + \tan^4 x}{\tan x}\) \(\frac{\sec^2 x + \tan^2x + \tan^4 x}{\tan x}\) \(\frac{\sec^2 x + \tan^2x(1 + \tan^2 x)}{\tan x}\) \(\frac{\sec^2 x + \tan^2x(\sec^2 x)}{\tan x}\) \(\frac{\sec^2 x(1 + \tan^2x)}{\tan x}\) \(\frac{\sec^2 x(\sec^2 x)}{\tan x}\) \(\frac{\sec^4 x}{\tan x}\) \(\cot x\sec^4 x\) = LEFT HAND SIDE
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
thats the complete solution; see if it makes sense
 2 years ago

jishan Group TitleBest ResponseYou've already chosen the best response.0
good solve ganeshie.,...........
 2 years ago

rubypearl11 Group TitleBest ResponseYou've already chosen the best response.0
How did you get rid of the tan^4x? @ganeshie8?
 one year ago

mayaal Group TitleBest ResponseYou've already chosen the best response.1
@ganeshie8 i dont understand ur solution
 4 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
hmm which line ?
 4 months ago

mayaal Group TitleBest ResponseYou've already chosen the best response.1
the 3rd line from the end.
 4 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
\[\large \frac{\sec^2 x + \tan^2x(\sec^2 x)}{\tan x}\]
 4 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
you're fine, till this line ?
 4 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
good, next factor out `sec^2x` from both terms, you get : \[\large \frac{\sec^2 x(1 + \tan^2x)}{\tan x}\]
 4 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
still fine ?
 4 months ago

mayaal Group TitleBest ResponseYou've already chosen the best response.1
oh,ok.so u factored out the sec^2x from the whole numerator?
 4 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
exactly !
 4 months ago

mayaal Group TitleBest ResponseYou've already chosen the best response.1
great!thnku very much @ganeshie8
 4 months ago
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