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logynklode

cot x sec4x = cot x + 2 tan x + tan3x

  • one year ago
  • one year ago

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  1. mahmit2012
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    Is this equation or identity?

    • one year ago
  2. logynklode
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    Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side of the equation.

    • one year ago
  3. ganeshie8
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    \(\cot x \sec^4 x = \cot x + 2 \tan x + \tan^3 x \)

    • one year ago
  4. ganeshie8
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    its like above ?

    • one year ago
  5. logynklode
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    huh?

    • one year ago
  6. ganeshie8
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    *the equation u seeing in ur assessment sheet, is it like the one ive posted above ?

    • one year ago
  7. logynklode
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    its tan cubed x at the end other then that yes

    • one year ago
  8. ganeshie8
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    ok thnks :) pick the side that has more terms, and do SOMETHING and try getting to the other side

    • one year ago
  9. ganeshie8
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    here, the right side has more terms, right ?

    • one year ago
  10. logynklode
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    what? the irght side has more terms yeah

    • one year ago
  11. ganeshie8
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    ya so we start with that side, and work, and prove that it equals left side.

    • one year ago
  12. logynklode
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    okay

    • one year ago
  13. ganeshie8
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    \(\cot x + 2\tan x + \tan^3 x\) \(\frac{1}{\tan x} + 2\tan x + \tan^3 x\) \(\frac{1+ 2\tan^2 x + \tan^4 x}{\tan x}\) \(\frac{1+ \tan^2 x + \tan^2x + \tan^4 x}{\tan x}\) \(\frac{\sec^2 x + \tan^2x + \tan^4 x}{\tan x}\) \(\frac{\sec^2 x + \tan^2x(1 + \tan^2 x)}{\tan x}\) \(\frac{\sec^2 x + \tan^2x(\sec^2 x)}{\tan x}\) \(\frac{\sec^2 x(1 + \tan^2x)}{\tan x}\) \(\frac{\sec^2 x(\sec^2 x)}{\tan x}\) \(\frac{\sec^4 x}{\tan x}\) \(\cot x\sec^4 x\) = LEFT HAND SIDE

    • one year ago
  14. ganeshie8
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    thats the complete solution; see if it makes sense

    • one year ago
  15. jishan
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    good solve ganeshie.,...........

    • one year ago
  16. rubypearl11
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    How did you get rid of the tan^4x? @ganeshie8?

    • 5 months ago
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