A community for students.
Here's the question you clicked on:
 0 viewing
logynklode
 3 years ago
cot x sec4x = cot x + 2 tan x + tan3x
logynklode
 3 years ago
cot x sec4x = cot x + 2 tan x + tan3x

This Question is Closed

mahmit2012
 3 years ago
Best ResponseYou've already chosen the best response.0Is this equation or identity?

logynklode
 3 years ago
Best ResponseYou've already chosen the best response.0Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side of the equation.

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.13\(\cot x \sec^4 x = \cot x + 2 \tan x + \tan^3 x \)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.13*the equation u seeing in ur assessment sheet, is it like the one ive posted above ?

logynklode
 3 years ago
Best ResponseYou've already chosen the best response.0its tan cubed x at the end other then that yes

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.13ok thnks :) pick the side that has more terms, and do SOMETHING and try getting to the other side

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.13here, the right side has more terms, right ?

logynklode
 3 years ago
Best ResponseYou've already chosen the best response.0what? the irght side has more terms yeah

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.13ya so we start with that side, and work, and prove that it equals left side.

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.13\(\cot x + 2\tan x + \tan^3 x\) \(\frac{1}{\tan x} + 2\tan x + \tan^3 x\) \(\frac{1+ 2\tan^2 x + \tan^4 x}{\tan x}\) \(\frac{1+ \tan^2 x + \tan^2x + \tan^4 x}{\tan x}\) \(\frac{\sec^2 x + \tan^2x + \tan^4 x}{\tan x}\) \(\frac{\sec^2 x + \tan^2x(1 + \tan^2 x)}{\tan x}\) \(\frac{\sec^2 x + \tan^2x(\sec^2 x)}{\tan x}\) \(\frac{\sec^2 x(1 + \tan^2x)}{\tan x}\) \(\frac{\sec^2 x(\sec^2 x)}{\tan x}\) \(\frac{\sec^4 x}{\tan x}\) \(\cot x\sec^4 x\) = LEFT HAND SIDE

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.13thats the complete solution; see if it makes sense

jishan
 3 years ago
Best ResponseYou've already chosen the best response.0good solve ganeshie.,...........

rubypearl11
 2 years ago
Best ResponseYou've already chosen the best response.0How did you get rid of the tan^4x? @ganeshie8?

mayaal
 one year ago
Best ResponseYou've already chosen the best response.1@ganeshie8 i dont understand ur solution

mayaal
 one year ago
Best ResponseYou've already chosen the best response.1the 3rd line from the end.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.13\[\large \frac{\sec^2 x + \tan^2x(\sec^2 x)}{\tan x}\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.13you're fine, till this line ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.13good, next factor out `sec^2x` from both terms, you get : \[\large \frac{\sec^2 x(1 + \tan^2x)}{\tan x}\]

mayaal
 one year ago
Best ResponseYou've already chosen the best response.1oh,ok.so u factored out the sec^2x from the whole numerator?

mayaal
 one year ago
Best ResponseYou've already chosen the best response.1great!thnku very much @ganeshie8
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.