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anonymous
 4 years ago
cot x sec4x = cot x + 2 tan x + tan3x
anonymous
 4 years ago
cot x sec4x = cot x + 2 tan x + tan3x

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is this equation or identity?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side of the equation.

ganeshie8
 4 years ago
Best ResponseYou've already chosen the best response.14\(\cot x \sec^4 x = \cot x + 2 \tan x + \tan^3 x \)

ganeshie8
 4 years ago
Best ResponseYou've already chosen the best response.14*the equation u seeing in ur assessment sheet, is it like the one ive posted above ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0its tan cubed x at the end other then that yes

ganeshie8
 4 years ago
Best ResponseYou've already chosen the best response.14ok thnks :) pick the side that has more terms, and do SOMETHING and try getting to the other side

ganeshie8
 4 years ago
Best ResponseYou've already chosen the best response.14here, the right side has more terms, right ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what? the irght side has more terms yeah

ganeshie8
 4 years ago
Best ResponseYou've already chosen the best response.14ya so we start with that side, and work, and prove that it equals left side.

ganeshie8
 4 years ago
Best ResponseYou've already chosen the best response.14\(\cot x + 2\tan x + \tan^3 x\) \(\frac{1}{\tan x} + 2\tan x + \tan^3 x\) \(\frac{1+ 2\tan^2 x + \tan^4 x}{\tan x}\) \(\frac{1+ \tan^2 x + \tan^2x + \tan^4 x}{\tan x}\) \(\frac{\sec^2 x + \tan^2x + \tan^4 x}{\tan x}\) \(\frac{\sec^2 x + \tan^2x(1 + \tan^2 x)}{\tan x}\) \(\frac{\sec^2 x + \tan^2x(\sec^2 x)}{\tan x}\) \(\frac{\sec^2 x(1 + \tan^2x)}{\tan x}\) \(\frac{\sec^2 x(\sec^2 x)}{\tan x}\) \(\frac{\sec^4 x}{\tan x}\) \(\cot x\sec^4 x\) = LEFT HAND SIDE

ganeshie8
 4 years ago
Best ResponseYou've already chosen the best response.14thats the complete solution; see if it makes sense

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0good solve ganeshie.,...........

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0How did you get rid of the tan^4x? @ganeshie8?

mayaal
 2 years ago
Best ResponseYou've already chosen the best response.1@ganeshie8 i dont understand ur solution

mayaal
 2 years ago
Best ResponseYou've already chosen the best response.1the 3rd line from the end.

ganeshie8
 2 years ago
Best ResponseYou've already chosen the best response.14\[\large \frac{\sec^2 x + \tan^2x(\sec^2 x)}{\tan x}\]

ganeshie8
 2 years ago
Best ResponseYou've already chosen the best response.14you're fine, till this line ?

ganeshie8
 2 years ago
Best ResponseYou've already chosen the best response.14good, next factor out `sec^2x` from both terms, you get : \[\large \frac{\sec^2 x(1 + \tan^2x)}{\tan x}\]

mayaal
 2 years ago
Best ResponseYou've already chosen the best response.1oh,ok.so u factored out the sec^2x from the whole numerator?

mayaal
 2 years ago
Best ResponseYou've already chosen the best response.1great!thnku very much @ganeshie8
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