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mahmit2012 Group TitleBest ResponseYou've already chosen the best response.0
Is this equation or identity?
 one year ago

logynklode Group TitleBest ResponseYou've already chosen the best response.0
Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side of the equation.
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
\(\cot x \sec^4 x = \cot x + 2 \tan x + \tan^3 x \)
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
its like above ?
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
*the equation u seeing in ur assessment sheet, is it like the one ive posted above ?
 one year ago

logynklode Group TitleBest ResponseYou've already chosen the best response.0
its tan cubed x at the end other then that yes
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
ok thnks :) pick the side that has more terms, and do SOMETHING and try getting to the other side
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
here, the right side has more terms, right ?
 one year ago

logynklode Group TitleBest ResponseYou've already chosen the best response.0
what? the irght side has more terms yeah
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
ya so we start with that side, and work, and prove that it equals left side.
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
\(\cot x + 2\tan x + \tan^3 x\) \(\frac{1}{\tan x} + 2\tan x + \tan^3 x\) \(\frac{1+ 2\tan^2 x + \tan^4 x}{\tan x}\) \(\frac{1+ \tan^2 x + \tan^2x + \tan^4 x}{\tan x}\) \(\frac{\sec^2 x + \tan^2x + \tan^4 x}{\tan x}\) \(\frac{\sec^2 x + \tan^2x(1 + \tan^2 x)}{\tan x}\) \(\frac{\sec^2 x + \tan^2x(\sec^2 x)}{\tan x}\) \(\frac{\sec^2 x(1 + \tan^2x)}{\tan x}\) \(\frac{\sec^2 x(\sec^2 x)}{\tan x}\) \(\frac{\sec^4 x}{\tan x}\) \(\cot x\sec^4 x\) = LEFT HAND SIDE
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
thats the complete solution; see if it makes sense
 one year ago

jishan Group TitleBest ResponseYou've already chosen the best response.0
good solve ganeshie.,...........
 one year ago

rubypearl11 Group TitleBest ResponseYou've already chosen the best response.0
How did you get rid of the tan^4x? @ganeshie8?
 11 months ago

mayaal Group TitleBest ResponseYou've already chosen the best response.1
@ganeshie8 i dont understand ur solution
 3 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
hmm which line ?
 3 months ago

mayaal Group TitleBest ResponseYou've already chosen the best response.1
the 3rd line from the end.
 3 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
\[\large \frac{\sec^2 x + \tan^2x(\sec^2 x)}{\tan x}\]
 3 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
you're fine, till this line ?
 3 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
good, next factor out `sec^2x` from both terms, you get : \[\large \frac{\sec^2 x(1 + \tan^2x)}{\tan x}\]
 3 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
still fine ?
 3 months ago

mayaal Group TitleBest ResponseYou've already chosen the best response.1
oh,ok.so u factored out the sec^2x from the whole numerator?
 3 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.8
exactly !
 3 months ago

mayaal Group TitleBest ResponseYou've already chosen the best response.1
great!thnku very much @ganeshie8
 3 months ago
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