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k>0,k>2,k>4,k<4

(x+k)x=-4
x^2 + kx + 4 = 0

First, rearrange the equation into the form ax^2 + bx + c = 0 after expanding the original equation.

what next ?

For two real solutions
b^2 - 4ac > 0

x^2 + kx + 4 = 0
k^2 - 16 > 0

k >4 < Answer

yup..)