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hba

  • 2 years ago

A possible interval of values of k for which the equation (x+k)x=-4,have two real solutions is :

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  1. hba
    • 2 years ago
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    k>0,k>2,k>4,k<4

  2. Yahoo!
    • 2 years ago
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    (x+k)x=-4 x^2 + kx + 4 = 0

  3. tcarroll010
    • 2 years ago
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    First, rearrange the equation into the form ax^2 + bx + c = 0 after expanding the original equation.

  4. hba
    • 2 years ago
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    I got that already @Yahoo!

  5. hba
    • 2 years ago
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    what next ?

  6. Yahoo!
    • 2 years ago
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    For two real solutions b^2 - 4ac > 0

  7. Yahoo!
    • 2 years ago
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    x^2 + kx + 4 = 0 k^2 - 16 > 0

  8. hba
    • 2 years ago
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    k >4 < Answer

  9. Yahoo!
    • 2 years ago
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    yup..)

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