hba
A possible interval of values of k for which the equation (x+k)x=4,have two real solutions is :



This Question is Closed

hba
Best Response
You've already chosen the best response.
0
k>0,k>2,k>4,k<4

Yahoo!
Best Response
You've already chosen the best response.
0
(x+k)x=4
x^2 + kx + 4 = 0

tcarroll010
Best Response
You've already chosen the best response.
0
First, rearrange the equation into the form ax^2 + bx + c = 0 after expanding the original equation.

hba
Best Response
You've already chosen the best response.
0
I got that already @Yahoo!

hba
Best Response
You've already chosen the best response.
0
what next ?

Yahoo!
Best Response
You've already chosen the best response.
0
For two real solutions
b^2  4ac > 0

Yahoo!
Best Response
You've already chosen the best response.
0
x^2 + kx + 4 = 0
k^2  16 > 0

hba
Best Response
You've already chosen the best response.
0
k >4 < Answer

Yahoo!
Best Response
You've already chosen the best response.
0
yup..)