Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

hba

  • 3 years ago

A possible interval of values of k for which the equation (x+k)x=-4,have two real solutions is :

  • This Question is Closed
  1. hba
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    k>0,k>2,k>4,k<4

  2. Yahoo!
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    (x+k)x=-4 x^2 + kx + 4 = 0

  3. tcarroll010
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    First, rearrange the equation into the form ax^2 + bx + c = 0 after expanding the original equation.

  4. hba
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I got that already @Yahoo!

  5. hba
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what next ?

  6. Yahoo!
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    For two real solutions b^2 - 4ac > 0

  7. Yahoo!
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    x^2 + kx + 4 = 0 k^2 - 16 > 0

  8. hba
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    k >4 < Answer

  9. Yahoo!
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yup..)

  10. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy