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A possible interval of values of k for which the equation (x+k)x=4,have two real solutions is :
 one year ago
 one year ago
A possible interval of values of k for which the equation (x+k)x=4,have two real solutions is :
 one year ago
 one year ago

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Yahoo!Best ResponseYou've already chosen the best response.0
(x+k)x=4 x^2 + kx + 4 = 0
 one year ago

tcarroll010Best ResponseYou've already chosen the best response.0
First, rearrange the equation into the form ax^2 + bx + c = 0 after expanding the original equation.
 one year ago

hbaBest ResponseYou've already chosen the best response.0
I got that already @Yahoo!
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
For two real solutions b^2  4ac > 0
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
x^2 + kx + 4 = 0 k^2  16 > 0
 one year ago
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