## anonymous 3 years ago A seconds pendulum is a pendulum whose period is precisely two seconds; one second for a swing in one direction and one second for the return swing. The length of a seconds pendulum in Tokyo, Japan is 0.9927 m and that in Cambridge, England is 0.9942 m. The ratio of the acceleration due to gravity at the two places, gT /gL is

1. anonymous

0.9987. 1.0150. 1.0008. 1.0015. 1.0000. which one is correct !!

2. anonymous

The period of the pendulum is given by: $\huge{T=2\pi \sqrt{\frac{L}{g}}}$ Since the period of each pendulum is the same you can set them equal to each other through equations: $\huge{T_{T}=T_{C}}$ $\huge{2\pi \sqrt{\frac{L_T}{g_T}}=2\pi \sqrt{\frac{L_C}{g_C}}}$ From here you should be able to rearrange to solve the ratio: $\huge{\frac{g_T}{g_C}=?}$

3. anonymous

is the period of a pendulum a given formula?

4. anonymous

yes...see first equation above. T = Period L = Length g = Force of gravity

5. anonymous

so you will have to memorise it

6. anonymous

I'm not sure what you'll have to do. It depends on the context in which you were taught it i suppose