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shico
Group Title
A seconds pendulum is a pendulum whose period is precisely two seconds; one second for a swing in one direction and one second for the return swing. The length of a seconds pendulum in Tokyo, Japan is 0.9927 m and that in Cambridge, England is 0.9942 m. The ratio of the acceleration due to gravity at the two places, gT /gL is
 one year ago
 one year ago
shico Group Title
A seconds pendulum is a pendulum whose period is precisely two seconds; one second for a swing in one direction and one second for the return swing. The length of a seconds pendulum in Tokyo, Japan is 0.9927 m and that in Cambridge, England is 0.9942 m. The ratio of the acceleration due to gravity at the two places, gT /gL is
 one year ago
 one year ago

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shico Group TitleBest ResponseYou've already chosen the best response.0
0.9987. 1.0150. 1.0008. 1.0015. 1.0000. which one is correct !!
 one year ago

Mathmuse Group TitleBest ResponseYou've already chosen the best response.0
The period of the pendulum is given by: \[\huge{T=2\pi \sqrt{\frac{L}{g}}}\] Since the period of each pendulum is the same you can set them equal to each other through equations: \[\huge{T_{T}=T_{C}}\] \[\huge{2\pi \sqrt{\frac{L_T}{g_T}}=2\pi \sqrt{\frac{L_C}{g_C}}}\] From here you should be able to rearrange to solve the ratio: \[\huge{\frac{g_T}{g_C}=?}\]
 one year ago

Skaematik Group TitleBest ResponseYou've already chosen the best response.0
is the period of a pendulum a given formula?
 one year ago

Mathmuse Group TitleBest ResponseYou've already chosen the best response.0
yes...see first equation above. T = Period L = Length g = Force of gravity
 one year ago

Skaematik Group TitleBest ResponseYou've already chosen the best response.0
so you will have to memorise it
 one year ago

Mathmuse Group TitleBest ResponseYou've already chosen the best response.0
I'm not sure what you'll have to do. It depends on the context in which you were taught it i suppose
 one year ago
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