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vivalakoda Group TitleBest ResponseYou've already chosen the best response.0
\[\left( 7√54 \right)  \left( 5+√24 \right)\]
 one year ago

Galice Group TitleBest ResponseYou've already chosen the best response.1
You can split each radical up like so: \[\sqrt{54} = \sqrt{6 \times 9}\] You can also perform the same for the other radical: \[\sqrt{24} = \sqrt{6 \times 4}\] Once you've done that, you can pull out any perfect squares that you have found. In this case, you've just found 9 and 4, which root down to 3 and 2, respectively. Now you have: \[\left( 7 3\sqrt{6} \right)  \left( 5 + 2\sqrt{6} \right)\] Does that help?
 one year ago

vivalakoda Group TitleBest ResponseYou've already chosen the best response.0
I've gotten as far as that, simplifying the radicals. But I'm confused as to how to go about the subtracting with a subtraction problem within a subtraction problem
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.1
Distribute 1 to the brackets..
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.1
\[1(5+2 \sqrt{6}) = ??\]
 one year ago

vivalakoda Group TitleBest ResponseYou've already chosen the best response.0
= 52√6
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.1
Now: \[7 3\sqrt{6}  5  2\sqrt{6} = ??\]
 one year ago

vivalakoda Group TitleBest ResponseYou've already chosen the best response.0
25√6? D:
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.1
Then where is the problem?? Yes, well done...
 one year ago

vivalakoda Group TitleBest ResponseYou've already chosen the best response.0
I guess I just needed a walkthrough. Hah thanks!
 one year ago
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