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anonymous
 3 years ago
Subtracting radicals?
anonymous
 3 years ago
Subtracting radicals?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\left( 7√54 \right)  \left( 5+√24 \right)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You can split each radical up like so: \[\sqrt{54} = \sqrt{6 \times 9}\] You can also perform the same for the other radical: \[\sqrt{24} = \sqrt{6 \times 4}\] Once you've done that, you can pull out any perfect squares that you have found. In this case, you've just found 9 and 4, which root down to 3 and 2, respectively. Now you have: \[\left( 7 3\sqrt{6} \right)  \left( 5 + 2\sqrt{6} \right)\] Does that help?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I've gotten as far as that, simplifying the radicals. But I'm confused as to how to go about the subtracting with a subtraction problem within a subtraction problem

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Distribute 1 to the brackets..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[1(5+2 \sqrt{6}) = ??\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Now: \[7 3\sqrt{6}  5  2\sqrt{6} = ??\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Then where is the problem?? Yes, well done...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I guess I just needed a walkthrough. Hah thanks!
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