A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Hey guys Does anyone can help me with this?
H9P1: RESPONSE TO A DELAYED IMPULSE
The current source puts out an impulse of area A=2/π=0.64 Coulombs at time t=9.0s.
At t=0 the state is: vC(0)=0.0 and iL(0)=1.0.
The equation governing the evolution of the inductor current in this circuit is
d2iL(t)dt2+1LCiL(t)=ALCδ(t−9.0)
and this H9P2 SOC
Consider the second order low pass filter circuit shown below.?
anonymous
 4 years ago
Hey guys Does anyone can help me with this? H9P1: RESPONSE TO A DELAYED IMPULSE The current source puts out an impulse of area A=2/π=0.64 Coulombs at time t=9.0s. At t=0 the state is: vC(0)=0.0 and iL(0)=1.0. The equation governing the evolution of the inductor current in this circuit is d2iL(t)dt2+1LCiL(t)=ALCδ(t−9.0) and this H9P2 SOC Consider the second order low pass filter circuit shown below.?

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0about H9P2.. if anyone can tell me the formula. I'll be thankful and H9P1 how can I solve it ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0H9P1 1 0.25 2 22.5 3 22.5 4 5.51091059616e16 5 70.6858347058 6 0 7 0 8 0 H9P2 1 L*C 2 L/R 3 1 4 sqrt(1/(L*C))/(2*pi) 5 1/(2*R*C) 6 (1/R)*sqrt(L/C) 7 2*sqrt(L/C)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0CHEK BEST RESPONSE IF U GET RIGHT ANSWERS.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(1/R)*sqrt(L/C) 2*sqrt(L/C) these are wrong answers, plz let us know the correct one acid16

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thats answers is working for me... i dont know what is wrong... check them again..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I ve checked 4 to 5 times but it doesn't work........ probably a changed question! of what is it the formula 2*sqrt(L/C)?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0And what's the formula to calculate H9P1 2ND QUESTION? from which u got the following ans... 2... 22.5 can you plz let me know acid16

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the answer 22.5 both of them and the answer 70.6858347058 of H9P1 are not correct here .. idk why... and H9P2 (1/R)*sqrt(L/C) 2*sqrt(L/C) are not correct too.. do you know why ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0H9P1 1 sqrt(1/(L*C)) / (2*pi) 2 ½ * L * iL^2 3 the same as 2 4 iL (t) = cos(2*pi*f*t) 5 vC(t) = L*2*pi*f*sin(2*pi*f*t)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0just try this formulas, maybe u have diferent values..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I ve checked 4 to 5 times but it doesn't work........ probably a changed question! of what is it the formula 2*sqrt(L/C) acid16?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeeah.. it's not this answer !

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm having problems with 2 22.5 3 22.5 5 70.6858347058

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and the formulas (1/R)*sqrt(L/C) 2*sqrt(L/C).. it doesn't work n' idk why

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0h9p1 is solved but P2 is not having green tick for the last 2 acid16 thanx alot

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the formulas are R*sqrt(C/L) 0.5*sqrt(L/C)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.