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ursularoxursox Group Title

2x^2-x-3=0 I got x=0 x=-3/2 Did i solve correctly?

  • one year ago
  • one year ago

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  1. waterineyes Group Title
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    0 cannot be the solution I think..

    • one year ago
  2. waterineyes Group Title
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    Put 0 back in the equation in place of x, you will not get 0...

    • one year ago
  3. ajprincess Group Title
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    I dnt thnk x=0 is right. \(2x^2-x-3=0\) \(2x^2-3x+2x-3=0\) \(x(2x-3)+1(2x-3)=0\) \((x+1)(2x-3)=0\) \(x+1=0 ~or ~ 2x-3=0\)

    • one year ago
  4. waterineyes Group Title
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    Getting @ursularoxursox

    • one year ago
  5. ursularoxursox Group Title
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    i'm still having a difficult time understanding the equation

    • one year ago
  6. ursularoxursox Group Title
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    i understand now. thanks for the help everyone!

    • one year ago
  7. ajprincess Group Title
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    welcome:)

    • one year ago
  8. ajprincess Group Title
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    If anythng is not clear plz ask:)

    • one year ago
  9. ursularoxursox Group Title
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    I think I did another one wrong, can someone please guide me? The equation is 6x^2-5x-4=0 The first time I solved I got x=5/6 and x=-1 The second time I solved I got x=-1/6 and x=4 I don't think either are correct

    • one year ago
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