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ursularoxursox

  • 3 years ago

2x^2-x-3=0 I got x=0 x=-3/2 Did i solve correctly?

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  1. waterineyes
    • 3 years ago
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    0 cannot be the solution I think..

  2. waterineyes
    • 3 years ago
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    Put 0 back in the equation in place of x, you will not get 0...

  3. ajprincess
    • 3 years ago
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    I dnt thnk x=0 is right. \(2x^2-x-3=0\) \(2x^2-3x+2x-3=0\) \(x(2x-3)+1(2x-3)=0\) \((x+1)(2x-3)=0\) \(x+1=0 ~or ~ 2x-3=0\)

  4. waterineyes
    • 3 years ago
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    Getting @ursularoxursox

  5. ursularoxursox
    • 3 years ago
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    i'm still having a difficult time understanding the equation

  6. ursularoxursox
    • 3 years ago
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    i understand now. thanks for the help everyone!

  7. ajprincess
    • 3 years ago
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    welcome:)

  8. ajprincess
    • 3 years ago
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    If anythng is not clear plz ask:)

  9. ursularoxursox
    • 3 years ago
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    I think I did another one wrong, can someone please guide me? The equation is 6x^2-5x-4=0 The first time I solved I got x=5/6 and x=-1 The second time I solved I got x=-1/6 and x=4 I don't think either are correct

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