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waterineyesBest ResponseYou've already chosen the best response.1
0 cannot be the solution I think..
 one year ago

waterineyesBest ResponseYou've already chosen the best response.1
Put 0 back in the equation in place of x, you will not get 0...
 one year ago

ajprincessBest ResponseYou've already chosen the best response.2
I dnt thnk x=0 is right. \(2x^2x3=0\) \(2x^23x+2x3=0\) \(x(2x3)+1(2x3)=0\) \((x+1)(2x3)=0\) \(x+1=0 ~or ~ 2x3=0\)
 one year ago

waterineyesBest ResponseYou've already chosen the best response.1
Getting @ursularoxursox
 one year ago

ursularoxursoxBest ResponseYou've already chosen the best response.0
i'm still having a difficult time understanding the equation
 one year ago

ursularoxursoxBest ResponseYou've already chosen the best response.0
i understand now. thanks for the help everyone!
 one year ago

ajprincessBest ResponseYou've already chosen the best response.2
If anythng is not clear plz ask:)
 one year ago

ursularoxursoxBest ResponseYou've already chosen the best response.0
I think I did another one wrong, can someone please guide me? The equation is 6x^25x4=0 The first time I solved I got x=5/6 and x=1 The second time I solved I got x=1/6 and x=4 I don't think either are correct
 one year ago
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