y+10)/(y+3)= (y+1)/(y-1)
To have the same denominator for both fractions, we multiply the first fraction by (y-1) and the second fraction by (y+3)
(y-1)(y+10)-(y+1)(y+3) / (y+3) (y-1)
Do the multiplications
(y^2-y+10y-10-y^2-y-3y-3)/ (y-1) (y+3)
Simplify the same terms
(5y-13)/(y-1)(y+3
(3y+21)/(7y)-(4y-7)/6=(7y-10)/(3y)-(14y-… multiply by 42y on both sides
6(3y+21)-7y(4y-7)=14(7y-10)-2y(14y-2)
18y+126-28y^2+49y=98y-140-28y^2+4y
35y=266
y=226/35
y=38/5