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|dw:1353084189037:dw|
@ajprincess i need help
Cross multiply and plz tell me vat u get?

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Other answers:

i think my answers is 13/5
Can u plz show me ur work?
y+10)/(y+3)= (y+1)/(y-1) To have the same denominator for both fractions, we multiply the first fraction by (y-1) and the second fraction by (y+3) (y-1)(y+10)-(y+1)(y+3) / (y+3) (y-1) Do the multiplications (y^2-y+10y-10-y^2-y-3y-3)/ (y-1) (y+3) Simplify the same terms (5y-13)/(y-1)(y+3
13/5
yup perfect:) Great work:)
Solve for y:
|dw:1353084899750:dw|
Is this the question? \[\frac{ 3(y+7) }{ 7y }-\frac{ 9y-7 }{ 6 }=\frac{ 7+10 }{ 3y}-\frac{ 2(7y-1) }{ 21}\]
(3y+21)/(7y)-(4y-7)/6=(7y-10)/(3y)-(14y-… multiply by 42y on both sides 6(3y+21)-7y(4y-7)=14(7y-10)-2y(14y-2) 18y+126-28y^2+49y=98y-140-28y^2+4y 35y=266 y=226/35 y=38/5
i think -2/5
yes

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