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waterineyes Group TitleBest ResponseYou've already chosen the best response.0
Is this derivative with first term only??
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
That's not an equation, it's an expression and so in this state is useless
 2 years ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.0
It is totally useful: \[e^{x} +x \cdot e^{x} \implies e^{x}(x1)\]
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
Only if you've got the problem.
 2 years ago
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