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heathernelly

  • 2 years ago

help pleasee?

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  1. philo1234
    • 2 years ago
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    Part 1: The index on the radicals are the same (2) so we can write that as a single radical. \[\sqrt{50*(x^{7})*(x^{1})*(y^{7})*(y ^{4})}\] Then simplify this. What do you get?

  2. heathernelly
    • 2 years ago
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    50 x^8y^11?:/

  3. philo1234
    • 2 years ago
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    I got kicked off.

  4. philo1234
    • 2 years ago
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    Correction left out the 6: \[\sqrt{50*6*x^{7}*x ^{1}*y^{7}*y ^{4}}\]

  5. philo1234
    • 2 years ago
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    so we have: \[\sqrt{300x ^{8}y ^{11}}\]

  6. philo1234
    • 2 years ago
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    So what is the greatest factor of 300 that can be written as a square?

  7. philo1234
    • 2 years ago
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    OK, The factor of 300 we are going to choose is 3*100, where 100 = 10^2 Rewrite equation: \[\sqrt{10^{2}*3*x ^{8}*y}\]

  8. philo1234
    • 2 years ago
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    That last term should be y^11

  9. heathernelly
    • 2 years ago
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    okay, i switched computers, sorry about that!:(

  10. philo1234
    • 2 years ago
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    So our index is 2 on our radical. So we can divide each exponent under the radical by 2: for 10^2: 2/2 = 10^1 for 3^1 = 1/2 = 3^1/2 for x^8: 8/2 = x^4 for y^11: y^10/2 * y^1/2 = y^5 *y^1/2 So this would simplify to: \[10x ^{4}y^{5} \sqrt{3y}\]

  11. heathernelly
    • 2 years ago
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    thank you phil!!! :D it makes more sense now

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