## heathernelly Group Title help pleasee? 2 years ago 2 years ago

1. philo1234

Part 1: The index on the radicals are the same (2) so we can write that as a single radical. $\sqrt{50*(x^{7})*(x^{1})*(y^{7})*(y ^{4})}$ Then simplify this. What do you get?

2. heathernelly

50 x^8y^11?:/

3. philo1234

I got kicked off.

4. philo1234

Correction left out the 6: $\sqrt{50*6*x^{7}*x ^{1}*y^{7}*y ^{4}}$

5. philo1234

so we have: $\sqrt{300x ^{8}y ^{11}}$

6. philo1234

So what is the greatest factor of 300 that can be written as a square?

7. philo1234

OK, The factor of 300 we are going to choose is 3*100, where 100 = 10^2 Rewrite equation: $\sqrt{10^{2}*3*x ^{8}*y}$

8. philo1234

That last term should be y^11

9. heathernelly

okay, i switched computers, sorry about that!:(

10. philo1234

So our index is 2 on our radical. So we can divide each exponent under the radical by 2: for 10^2: 2/2 = 10^1 for 3^1 = 1/2 = 3^1/2 for x^8: 8/2 = x^4 for y^11: y^10/2 * y^1/2 = y^5 *y^1/2 So this would simplify to: $10x ^{4}y^{5} \sqrt{3y}$

11. heathernelly

thank you phil!!! :D it makes more sense now