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How to find Solution to differential equation
(x  4) y^{4} dx  x^{3} (y^{2}  3 ) dy = 0
 one year ago
 one year ago
How to find Solution to differential equation (x  4) y^{4} dx  x^{3} (y^{2}  3 ) dy = 0
 one year ago
 one year ago

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gerryliyanaBest ResponseYou've already chosen the best response.0
How to find Solution to not exact differential equation \[(x  4) y^{4} dx  x^{3} (y^{2}  3 ) dy = 0\]
 one year ago

henpenBest ResponseYou've already chosen the best response.1
Isn't \[\int\limits \frac{x4}{x^3}dx=\int\limits \frac{y^23}{y^4}dy\] enough?
 one year ago

henpenBest ResponseYou've already chosen the best response.1
It's probably not, I'm still pants at DE
 one year ago

henpenBest ResponseYou've already chosen the best response.1
Anyway: don't ask me HOW to integrate that (use Wolfram integrator if you just want the answer), it's probably some counterintuitive trig substitution.
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
i got \[ \frac{ 1 }{ x } + \frac{ 2 }{ x^{2} }\frac{ 1 }{ y } + \frac{ 1 }{ y^{3} } = C\] am i right?
 one year ago

henpenBest ResponseYou've already chosen the best response.1
http://integrals.wolfram.com/index.jsp?expr=%28x4%29%2Fx%5E3&random=false http://integrals.wolfram.com/index.jsp?expr=%28x%5E23%29%2Fx%5E4&random=false So your signs are wrong for either the x or y terms but it's fine other than that.
 one year ago

niksvaBest ResponseYou've already chosen the best response.0
@gerryliyana in this type of differntial eqution, we use separation of variable technique as we can see from this differential equation, variables can be separated easily
 one year ago

niksvaBest ResponseYou've already chosen the best response.0
@ gerryliyana i m getting 1/x + 2/x^2 + 1/ y^2  1 /y^3 = C where C is constant
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
ok @niksva but i got 1/x + 2/x^2 + 1/ y  1 /y^3 = C where C is constant
 one year ago

niksvaBest ResponseYou've already chosen the best response.0
omg my mistake it is 1/y
 one year ago
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