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KiArUnsYu
 2 years ago
Trevor is tiling his bathroom floor, which has an area that is represented as 175r5 square inches. Each tile has an area of sqrt(64r^17) . The total number of tiles used can be represented by the expression below.
175r^5/sqrt(64r^17)
Simplify the expression for the total number of tiles used. Show your work.
KiArUnsYu
 2 years ago
Trevor is tiling his bathroom floor, which has an area that is represented as 175r5 square inches. Each tile has an area of sqrt(64r^17) . The total number of tiles used can be represented by the expression below. 175r^5/sqrt(64r^17) Simplify the expression for the total number of tiles used. Show your work.

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ChmE
 2 years ago
Best ResponseYou've already chosen the best response.0lets work it one part at a time. I want to do the denominator first

ChmE
 2 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{64r^{17}}=\sqrt{64}\sqrt{r^{17}}=8(r^{17})^\frac{ 1 }{ 2 }=8r^{ \frac{ 17 }{ 2 }}\]

ChmE
 2 years ago
Best ResponseYou've already chosen the best response.0Does that make sense to you? Any questions on this part?

KiArUnsYu
 2 years ago
Best ResponseYou've already chosen the best response.0nope. i got that part.

ChmE
 2 years ago
Best ResponseYou've already chosen the best response.0Now put them together. \[\frac{ 175r^5 }{ 8r^{\frac{ 17 }{ 2 } }}=\frac{ 175 }{ 8 }\frac{ r^5 }{ r^{\frac{ 17 }{ 2 }} }\]

ChmE
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ x^n }{ x^m }=x^{(nm)}\]

ChmE
 2 years ago
Best ResponseYou've already chosen the best response.0using the formula I gave you. I want you to simplify the r's. let me know what you get

KiArUnsYu
 2 years ago
Best ResponseYou've already chosen the best response.0how would yu simplify the 17/2?

ChmE
 2 years ago
Best ResponseYou've already chosen the best response.0You can't that is the simplest fraction. but you need to cancel with r^5 in the numerator. Use the formula I gave x^(nm), where n and m are real numbers

KiArUnsYu
 2 years ago
Best ResponseYou've already chosen the best response.0oh okay. i think i got it

ChmE
 2 years ago
Best ResponseYou've already chosen the best response.0If you post your answer I'll check it.
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