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write an equation in slope intercept form of the line that contains (-1,7) and (3,-9)..............................help me!!!!

Mathematics
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Hi!\[\Huge{\color{RED}{\mathbb{Welcome \quad To \quad OpenStudy!}}}\]
Slope-intercept form: y = mx+b, where m is the slope of the line and b is the y-intercept. So use the equation above to find your answer just plug in the values given.
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so will it be y=5/3x+-2
Correct. replace that +- with just a -. y=5/3x-2
thank you so much for your help and time!!!!
No problem.
i just posted another question can you help me
hello
Post the link to your question on here. I can't find it on the list of questions. Is it in math?
That's the link for this same question. If you need to post a new question, click "Close". Then you'll be able to ask another question.
ok i did it it shoul be up there
I'm sorry! Is this your question: write an equation in slope intercept form of the line that contains (-1,7) and (3,-9) ? I didn't notice you had edited your original question!
First, find the slope. (-1,7) and (3,-9) \[m = \frac{ y2 - y1 }{ x2 - x }\]\[m = \frac{ -9 - 7 }{ 3 - (-1) } = \frac{ -9 - 7}{ 3+1 } = \frac{ -16 }{ 4 }= -4\]Slope is -4 -------------------- You have a point (-1, 7) and the slope(-4) so use the Point-Slope formula. y - y1 = m(x - x1) y - 7 = -4(x - (-1)) y - 7 = -4(x + 1) \[Distrbute\]y - 7 = -4x - 4 \[Add \quad 7\]y = -4x + 3

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