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its_me_th

  • 3 years ago

Write the equation of the line that is parallel to the line y = −3x + 12 and passes through the point (−1, 6). y = x + 7 y = −3x + 3 y = x + 3 y = −3x + 7

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  1. jazy
    • 3 years ago
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    What do you know about the new line? Parallel lines have the same slope. You also have a given point. Slope -3 Point (−1, 6) Use Point-Slope form. \[y - y1 = m(x - x1) \]y - 6 = -3(x - (-1)) y - 6 = -3(x + 1) \[Distribute\]y - 6 = -3x - 3 \[Add\quad 6\]y = -3x + 3

  2. jazy
    • 3 years ago
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    \[\Huge{\color{RED}{\mathbb{Welcome \quad To \quad OpenStudy!}}} \]

  3. jishan
    • 3 years ago
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    |dw:1353157301200:dw|

  4. jishan
    • 3 years ago
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    |dw:1353157401095:dw|

  5. jishan
    • 3 years ago
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    m=-3 line is parallel.

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