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Jone133
 3 years ago
Homework 11, Part1 question c)
For f=740k
L=0.65mH
RL=4ohm
RC=490k
It's the only question left, I tried values from 4 to 10, but it wont check, can't get a working formula either... Any help? :)
Jone133
 3 years ago
Homework 11, Part1 question c) For f=740k L=0.65mH RL=4ohm RC=490k It's the only question left, I tried values from 4 to 10, but it wont check, can't get a working formula either... Any help? :)

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fernandofei
 3 years ago
Best ResponseYou've already chosen the best response.1Hello C = 71.1645106214 pF Band = 5.54357213286 kHz If you second part has the value f=1180kHz C = 27.98 pF Band = 12.58kHz If you got green marks, please click in "best response" :D

gurukandula
 3 years ago
Best ResponseYou've already chosen the best response.0hi plz tell me the formula for bandwidth in h11p1

fernandofei
 3 years ago
Best ResponseYou've already chosen the best response.1For the bandwidth: dw = RL/L + 1/(Rc *C) after that, find f=(w/2*PI)/(1000) If works, please click at "Best response" :D

gurukandula
 3 years ago
Best ResponseYou've already chosen the best response.0hey it's not working my values are RL≈4.0Ω, L≈0.65mH, RC≈490.0kΩ, c=46pF, f=920.0kHz & for another one 3 bit f=1030.0kHz & c=36pF plzz. give me answer...

fernandofei
 3 years ago
Best ResponseYou've already chosen the best response.1Hello gurukandula I am not sure if this values are correct. Please, check if its ok :) For 920KHz C = 46.04 pF Bandwidth = 8.03428050596 KHz For 1030KHz C = 36.73 pF Bandwidth = 9.82248626529 KHz If works, please click at "Best Response"
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