Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

jess.white

  • 2 years ago

For the equation x^2+3x+j=0, find all the values of j such that the equation has two real number solutions. Show your work.

  • This Question is Closed
  1. raskalnikov
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    maybe you know that, roots find by the formula (-b+\sqrt{b ^{2}-4ac})\div2a\] so, b^2-4a.c must be bigger to zero for real number solutions.. i mean, 9-4*1*j bigger or equal to zero. so, \[0\le j <9/4\] for these interval, equation have 2 real solutions

  2. jess.white
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Can you show me how to write it down on my paper and how to show my work

  3. jess.white
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    im just so confused

  4. raskalnikov
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    in equation \[a*x ^{2}+b*x+c\] roots are \[x=(-b \pm \sqrt{b ^{2}-4*a*c})/2a\] this is the formula for finding roots. if \[\sqrt{b ^{2}-4*a*c})=0\] equation has just one real solution. if \[\sqrt{b ^{2}-4*a*c})<0\], equaiton has no real solution, if \[\sqrt{b ^{2}-4*a*c})>0\] system have 2 real solution. so, if we solve \[\sqrt{b ^{2}-4*a*c})>0\] \[9-4*j >0\] \[4*j<9\] \[j<9/4\]

  5. jess.white
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Thank you

  6. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.