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frx Group Title

Show that the equation \[z ^{3}+(-3+i)z^{2}+(6-3i)z+(-6-8i)=0\] has a pure imaginary root and then solve the equation. I know how to solve it by setting z=bi but what if the description would have said "has a pure real root " should i use z=a instead?

  • 2 years ago
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  1. hartnn Group Title
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    yes where a is real.

    • 2 years ago
  2. frx Group Title
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    Thank you, that was all :)

    • 2 years ago
  3. hartnn Group Title
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    quickest post ever! welcome ^_^

    • 2 years ago
  4. frx Group Title
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    Haha yeah that troubled me a bit since I always deal with pure imaginary ones :p I assume it's the same if it doesn't have any pure root then it's z=a+bi, right?:)

    • 2 years ago
  5. hartnn Group Title
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    right again :)

    • 2 years ago
  6. frx Group Title
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    Great, thanks!

    • 2 years ago
  7. hartnn Group Title
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    welcome ^_^

    • 2 years ago
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spraguer (Moderator)
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