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Show that the equation \[z ^{3}+(3+i)z^{2}+(63i)z+(68i)=0\] has a pure imaginary root and then solve the equation.
I know how to solve it by setting z=bi but what if the description would have said "has a pure real root " should i use z=a instead?
 one year ago
 one year ago
Show that the equation \[z ^{3}+(3+i)z^{2}+(63i)z+(68i)=0\] has a pure imaginary root and then solve the equation. I know how to solve it by setting z=bi but what if the description would have said "has a pure real root " should i use z=a instead?
 one year ago
 one year ago

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frxBest ResponseYou've already chosen the best response.1
Thank you, that was all :)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
quickest post ever! welcome ^_^
 one year ago

frxBest ResponseYou've already chosen the best response.1
Haha yeah that troubled me a bit since I always deal with pure imaginary ones :p I assume it's the same if it doesn't have any pure root then it's z=a+bi, right?:)
 one year ago
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