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frx
 3 years ago
Show that the equation \[z ^{3}+(3+i)z^{2}+(63i)z+(68i)=0\] has a pure imaginary root and then solve the equation.
I know how to solve it by setting z=bi but what if the description would have said "has a pure real root " should i use z=a instead?
frx
 3 years ago
Show that the equation \[z ^{3}+(3+i)z^{2}+(63i)z+(68i)=0\] has a pure imaginary root and then solve the equation. I know how to solve it by setting z=bi but what if the description would have said "has a pure real root " should i use z=a instead?

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hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1quickest post ever! welcome ^_^

frx
 3 years ago
Best ResponseYou've already chosen the best response.1Haha yeah that troubled me a bit since I always deal with pure imaginary ones :p I assume it's the same if it doesn't have any pure root then it's z=a+bi, right?:)
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