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clongfl
 2 years ago
k=1/3(b2a) solve for b
would you use the distributive property first or divide both sides by 1/3?
clongfl
 2 years ago
k=1/3(b2a) solve for b would you use the distributive property first or divide both sides by 1/3?

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Nurali
 2 years ago
Best ResponseYou've already chosen the best response.0K =1/3 (b – 2a) 3K = (b – 2a) 3K + 2a = b b = 3K + 2a

Nurali
 2 years ago
Best ResponseYou've already chosen the best response.0if correct please click best response

clongfl
 2 years ago
Best ResponseYou've already chosen the best response.0Why would you divide 1/3 before you would use the distributive property?

graydarl
 2 years ago
Best ResponseYou've already chosen the best response.1since 1/3 is only on one side u can move it or divide and the result will bee the same 3k=b2a and b=3k+2a

graydarl
 2 years ago
Best ResponseYou've already chosen the best response.1\[k=\frac{ 1 }{ 3 }*(b2a) *3 <=> 3k=b2a <=> b=3k+2a\]
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