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\[\Delta Q = m*c*\Delta T\]

is the specific heat for aluminum 0.920 J/(g c)? is that what ur asking for?

sure.

do you want me to google that in order to verify that it's the correct value or something?

ok so i take that and i multiply it by the mass which is 10g but how do i find the delta t?

from 120 to 80 is a change of?

and if u want u can google it i have it on my homework worksheet though

40 degrees

+40?

i think so

you lost 40 dollars

120 -> 80 is a change of -40

so it would be negative 40?

yes:)

ok so the formula would be 5*0.920J*-40 then i would get my answer?

it's 10 grams

oh sorry i was looking at the
wrong problem lol

so its -368 J

-40 dollars? or 40 dollars?

negative 40

"I lost negative forty dollars"
does anyone ever say that?

"lost" means "negative".

no lol so we would say we lost 40 thermal energy?

oooh ok thank you!!!