how much thermal energy is LOST while cooling a 10g block of aluminum form 120 celcius to 80 celcious

- anonymous

- chestercat

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- anonymous

\[\Delta Q = m*c*\Delta T\]

- anonymous

locate c, the specific heat of aluminum, on a table... use units for mass that agree with the units of the value you have for specific heat...

- anonymous

is the specific heat for aluminum 0.920 J/(g c)? is that what ur asking for?

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## More answers

- anonymous

sure.

- anonymous

do you want me to google that in order to verify that it's the correct value or something?

- anonymous

ok so i take that and i multiply it by the mass which is 10g but how do i find the delta t?

- anonymous

from 120 to 80 is a change of?

- anonymous

and if u want u can google it i have it on my homework worksheet though

- anonymous

40 degrees

- anonymous

+40?

- anonymous

i think so

- anonymous

if you had 6 twenties in your wallet and then you checked again in a few minutes and you only had 4 twenties, what happened?

- anonymous

you lost 40 dollars

- anonymous

120 -> 80 is a change of -40

- anonymous

so it would be negative 40?

- anonymous

yes:)

- anonymous

ok so the formula would be 5*0.920J*-40 then i would get my answer?

- anonymous

it's 10 grams

- anonymous

oh sorry i was looking at the
wrong problem lol

- anonymous

so its -368 J

- anonymous

sure but the question asks how much heat is lost... so if I asked you how much money you lost in the earlier example... what would you say?

- anonymous

-40 dollars? or 40 dollars?

- anonymous

negative 40

- anonymous

"I lost negative forty dollars"
does anyone ever say that?

- anonymous

"lost" means "negative".

- anonymous

no lol so we would say we lost 40 thermal energy?

- anonymous

temperature decreased -> heat was lost....
delta T is negative delta Q is negative
delta Q = -386 J means 386 J was lost

- anonymous

oooh ok thank you!!!

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