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faby9898
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how much thermal energy is LOST while cooling a 10g block of aluminum form 120 celcius to 80 celcious
 2 years ago
 2 years ago
faby9898 Group Title
how much thermal energy is LOST while cooling a 10g block of aluminum form 120 celcius to 80 celcious
 2 years ago
 2 years ago

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Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
\[\Delta Q = m*c*\Delta T\]
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
locate c, the specific heat of aluminum, on a table... use units for mass that agree with the units of the value you have for specific heat...
 2 years ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
is the specific heat for aluminum 0.920 J/(g c)? is that what ur asking for?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
do you want me to google that in order to verify that it's the correct value or something?
 2 years ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
ok so i take that and i multiply it by the mass which is 10g but how do i find the delta t?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
from 120 to 80 is a change of?
 2 years ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
and if u want u can google it i have it on my homework worksheet though
 2 years ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
40 degrees
 2 years ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
i think so
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
if you had 6 twenties in your wallet and then you checked again in a few minutes and you only had 4 twenties, what happened?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
you lost 40 dollars
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
120 > 80 is a change of 40
 2 years ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
so it would be negative 40?
 2 years ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
ok so the formula would be 5*0.920J*40 then i would get my answer?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
it's 10 grams
 2 years ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
oh sorry i was looking at the wrong problem lol
 2 years ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
so its 368 J
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
sure but the question asks how much heat is lost... so if I asked you how much money you lost in the earlier example... what would you say?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
40 dollars? or 40 dollars?
 2 years ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
negative 40
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
"I lost negative forty dollars" does anyone ever say that?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
"lost" means "negative".
 2 years ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
no lol so we would say we lost 40 thermal energy?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
temperature decreased > heat was lost.... delta T is negative delta Q is negative delta Q = 386 J means 386 J was lost
 2 years ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
oooh ok thank you!!!
 2 years ago
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