## faby9898 3 years ago how much thermal energy is LOST while cooling a 10g block of aluminum form 120 celcius to 80 celcious

1. Algebraic!

\[\Delta Q = m*c*\Delta T\]

2. Algebraic!

locate c, the specific heat of aluminum, on a table... use units for mass that agree with the units of the value you have for specific heat...

3. faby9898

is the specific heat for aluminum 0.920 J/(g c)? is that what ur asking for?

4. Algebraic!

sure.

5. Algebraic!

do you want me to google that in order to verify that it's the correct value or something?

6. faby9898

ok so i take that and i multiply it by the mass which is 10g but how do i find the delta t?

7. Algebraic!

from 120 to 80 is a change of?

8. faby9898

and if u want u can google it i have it on my homework worksheet though

9. faby9898

40 degrees

10. Algebraic!

+40?

11. faby9898

i think so

12. Algebraic!

if you had 6 twenties in your wallet and then you checked again in a few minutes and you only had 4 twenties, what happened?

13. Algebraic!

you lost 40 dollars

14. Algebraic!

120 -> 80 is a change of -40

15. faby9898

so it would be negative 40?

16. Algebraic!

yes:)

17. faby9898

ok so the formula would be 5*0.920J*-40 then i would get my answer?

18. Algebraic!

it's 10 grams

19. faby9898

oh sorry i was looking at the wrong problem lol

20. faby9898

so its -368 J

21. Algebraic!

sure but the question asks how much heat is lost... so if I asked you how much money you lost in the earlier example... what would you say?

22. Algebraic!

-40 dollars? or 40 dollars?

23. faby9898

negative 40

24. Algebraic!

"I lost negative forty dollars" does anyone ever say that?

25. Algebraic!

"lost" means "negative".

26. faby9898

no lol so we would say we lost 40 thermal energy?

27. Algebraic!

temperature decreased -> heat was lost.... delta T is negative delta Q is negative delta Q = -386 J means 386 J was lost

28. faby9898

oooh ok thank you!!!