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faby9898
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how much thermal energy is LOST while cooling a 10g block of aluminum form 120 celcius to 80 celcious
 one year ago
 one year ago
faby9898 Group Title
how much thermal energy is LOST while cooling a 10g block of aluminum form 120 celcius to 80 celcious
 one year ago
 one year ago

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Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
\[\Delta Q = m*c*\Delta T\]
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
locate c, the specific heat of aluminum, on a table... use units for mass that agree with the units of the value you have for specific heat...
 one year ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
is the specific heat for aluminum 0.920 J/(g c)? is that what ur asking for?
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
do you want me to google that in order to verify that it's the correct value or something?
 one year ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
ok so i take that and i multiply it by the mass which is 10g but how do i find the delta t?
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
from 120 to 80 is a change of?
 one year ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
and if u want u can google it i have it on my homework worksheet though
 one year ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
40 degrees
 one year ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
i think so
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
if you had 6 twenties in your wallet and then you checked again in a few minutes and you only had 4 twenties, what happened?
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
you lost 40 dollars
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
120 > 80 is a change of 40
 one year ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
so it would be negative 40?
 one year ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
ok so the formula would be 5*0.920J*40 then i would get my answer?
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
it's 10 grams
 one year ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
oh sorry i was looking at the wrong problem lol
 one year ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
so its 368 J
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
sure but the question asks how much heat is lost... so if I asked you how much money you lost in the earlier example... what would you say?
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
40 dollars? or 40 dollars?
 one year ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
negative 40
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
"I lost negative forty dollars" does anyone ever say that?
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
"lost" means "negative".
 one year ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
no lol so we would say we lost 40 thermal energy?
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
temperature decreased > heat was lost.... delta T is negative delta Q is negative delta Q = 386 J means 386 J was lost
 one year ago

faby9898 Group TitleBest ResponseYou've already chosen the best response.0
oooh ok thank you!!!
 one year ago
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