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AEB047 Group Title

Solve for x, y, z: x+y+z=12 6x-2y-z=16 3x+4y+2z=28

  • 2 years ago
  • 2 years ago

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  1. AEB047 Group Title
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    HELP!!!!!

    • 2 years ago
  2. _irawk_ Group Title
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    what are you stuck on?

    • 2 years ago
  3. Algebraic! Group Title
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    solve the first equation for x and substitute into the last two equations... then solve those two equations for y and z

    • 2 years ago
  4. AEB047 Group Title
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    I don't get any of it.

    • 2 years ago
  5. Algebraic! Group Title
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    "solve the first equation for x" move all the terms without 'x' in them to one side of the equal sign

    • 2 years ago
  6. Algebraic! Group Title
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    can you do that?

    • 2 years ago
  7. AEB047 Group Title
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    I know THAT. x=-y-z+12

    • 2 years ago
  8. Algebraic! Group Title
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    great.

    • 2 years ago
  9. AEB047 Group Title
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    6(-y-z+12)-2y-z=16

    • 2 years ago
  10. Algebraic! Group Title
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    "substitute into the last two equations." 6x-2y-z=16 - > 6(-y-z+12) -2y-z=16 3x+4y+2z=28 -> 3(-y-z+12) 4y+2z=28

    • 2 years ago
  11. Algebraic! Group Title
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    yep

    • 2 years ago
  12. Algebraic! Group Title
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    do some basic algebra to simplify... what are you left with?

    • 2 years ago
  13. Algebraic! Group Title
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    two equations with two unknowns...

    • 2 years ago
  14. Algebraic! Group Title
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    solve them the same way we just 'solved' for x...

    • 2 years ago
  15. Algebraic! Group Title
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    solve one equation for z or y.... substitute into the other equation.

    • 2 years ago
  16. AEB047 Group Title
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    what's16-72?

    • 2 years ago
  17. Algebraic! Group Title
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    good one.

    • 2 years ago
  18. AEB047 Group Title
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    never mind.

    • 2 years ago
  19. Arhin Group Title
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    x=4 y=0 z=8

    • 2 years ago
  20. jishan Group Title
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    x=4,y=0 & z=8

    • 2 years ago
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