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Solve for x, y, z: x+y+z=12 6x-2y-z=16 3x+4y+2z=28

Algebra
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HELP!!!!!
what are you stuck on?
solve the first equation for x and substitute into the last two equations... then solve those two equations for y and z

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Other answers:

I don't get any of it.
"solve the first equation for x" move all the terms without 'x' in them to one side of the equal sign
can you do that?
I know THAT. x=-y-z+12
great.
6(-y-z+12)-2y-z=16
"substitute into the last two equations." 6x-2y-z=16 - > 6(-y-z+12) -2y-z=16 3x+4y+2z=28 -> 3(-y-z+12) 4y+2z=28
yep
do some basic algebra to simplify... what are you left with?
two equations with two unknowns...
solve them the same way we just 'solved' for x...
solve one equation for z or y.... substitute into the other equation.
what's16-72?
good one.
never mind.
x=4 y=0 z=8
x=4,y=0 & z=8

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