AEB047
Solve for x, y, z:
x+y+z=12
6x2yz=16
3x+4y+2z=28



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AEB047
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HELP!!!!!

_irawk_
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what are you stuck on?

Algebraic!
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solve the first equation for x and substitute into the last two equations... then solve those two equations for y and z

AEB047
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I don't get any of it.

Algebraic!
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"solve the first equation for x"
move all the terms without 'x' in them to one side of the equal sign

Algebraic!
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can you do that?

AEB047
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I know THAT.
x=yz+12

Algebraic!
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great.

AEB047
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6(yz+12)2yz=16

Algebraic!
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"substitute into the last two equations."
6x2yz=16
 > 6(yz+12) 2yz=16
3x+4y+2z=28
> 3(yz+12) 4y+2z=28

Algebraic!
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yep

Algebraic!
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do some basic algebra to simplify... what are you left with?

Algebraic!
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two equations with two unknowns...

Algebraic!
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solve them the same way we just 'solved' for x...

Algebraic!
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solve one equation for z or y.... substitute into the other equation.

AEB047
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what's1672?

Algebraic!
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good one.

AEB047
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never mind.

Arhin
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x=4 y=0 z=8

jishan
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x=4,y=0 & z=8