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AEB047
 3 years ago
Solve for x, y, z:
x+y+z=12
6x2yz=16
3x+4y+2z=28
AEB047
 3 years ago
Solve for x, y, z: x+y+z=12 6x2yz=16 3x+4y+2z=28

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Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.1solve the first equation for x and substitute into the last two equations... then solve those two equations for y and z

Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.1"solve the first equation for x" move all the terms without 'x' in them to one side of the equal sign

Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.1"substitute into the last two equations." 6x2yz=16  > 6(yz+12) 2yz=16 3x+4y+2z=28 > 3(yz+12) 4y+2z=28

Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.1do some basic algebra to simplify... what are you left with?

Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.1two equations with two unknowns...

Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.1solve them the same way we just 'solved' for x...

Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.1solve one equation for z or y.... substitute into the other equation.
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