anonymous
  • anonymous
Solve for x, y, z: x+y+z=12 6x-2y-z=16 3x+4y+2z=28
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
HELP!!!!!
anonymous
  • anonymous
what are you stuck on?
anonymous
  • anonymous
solve the first equation for x and substitute into the last two equations... then solve those two equations for y and z

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anonymous
  • anonymous
I don't get any of it.
anonymous
  • anonymous
"solve the first equation for x" move all the terms without 'x' in them to one side of the equal sign
anonymous
  • anonymous
can you do that?
anonymous
  • anonymous
I know THAT. x=-y-z+12
anonymous
  • anonymous
great.
anonymous
  • anonymous
6(-y-z+12)-2y-z=16
anonymous
  • anonymous
"substitute into the last two equations." 6x-2y-z=16 - > 6(-y-z+12) -2y-z=16 3x+4y+2z=28 -> 3(-y-z+12) 4y+2z=28
anonymous
  • anonymous
yep
anonymous
  • anonymous
do some basic algebra to simplify... what are you left with?
anonymous
  • anonymous
two equations with two unknowns...
anonymous
  • anonymous
solve them the same way we just 'solved' for x...
anonymous
  • anonymous
solve one equation for z or y.... substitute into the other equation.
anonymous
  • anonymous
what's16-72?
anonymous
  • anonymous
good one.
anonymous
  • anonymous
never mind.
Arhin
  • Arhin
x=4 y=0 z=8
anonymous
  • anonymous
x=4,y=0 & z=8

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