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Solve for x, y, z: x+y+z=12 6x-2y-z=16 3x+4y+2z=28

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what are you stuck on?
solve the first equation for x and substitute into the last two equations... then solve those two equations for y and z

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Other answers:

I don't get any of it.
"solve the first equation for x" move all the terms without 'x' in them to one side of the equal sign
can you do that?
I know THAT. x=-y-z+12
"substitute into the last two equations." 6x-2y-z=16 - > 6(-y-z+12) -2y-z=16 3x+4y+2z=28 -> 3(-y-z+12) 4y+2z=28
do some basic algebra to simplify... what are you left with?
two equations with two unknowns...
solve them the same way we just 'solved' for x...
solve one equation for z or y.... substitute into the other equation.
good one.
never mind.
x=4 y=0 z=8
x=4,y=0 & z=8

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