Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Dido525

  • 2 years ago

Hyperbolic intergal

  • This Question is Closed
  1. Dido525
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1353111163841:dw|

  2. Dido525
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    No matter how many times I do it I keep getting the wrong answer.

  3. Dido525
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @zepdrix

  4. Dido525
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I believe the anti-derivative is: |dw:1353111289980:dw|

  5. zepdrix
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Hmm I'm not sure how you're able to deal with the fact that the outside term is a square. Is there a double angle formula for hyperbolic sine? Otherwise I would convert to exponentials and break it down from there. \[\large \sinh x=\frac{ e^x-e^{-x} }{ 2 }\] \[\large \sinh^2 x=\left(\frac{ e^x-e^{-x} }{ 2 }\right)^2=\left(\frac{ 1 }{ 4 }\right)(e^{2x}-e^{-2x}-2)\] Hopefully I expanded that correctly :O

  6. Dido525
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Well according to Wikipedia:

    1 Attachment
  7. Dido525
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    In this case a is 1.

  8. zepdrix
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Hmm yah it looks good. But if you're trying to enter this into webassign (or something similar), then maybe your teacher is looking for an answer in exponential form. Hmmmmm.

  9. Dido525
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    No No. It's a written :) .

  10. zepdrix
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Do you have the answer we're SUPPOSE to get, like in a book or anything? :D

  11. Dido525
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    No...

  12. zepdrix
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Then why do you think you're getting the wrong answer? XD

  13. zepdrix
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Oh, so you GAVE me the answer, you're just not sure how to get there? :O

  14. Dido525
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Wolfram.

  15. Dido525
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ohh wait...

  16. Dido525
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    No I didn't give you the answer. I just keep getting different answers every time.

  17. zepdrix
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\huge \int\limits_{0}^{1}\left(\frac{ 1 }{ 4 }\right)(e^{2x}-e^{-2x}-2) dx\] \[\huge =\left(\frac{ 1 }{ 4 }\right)\left(\left(\frac{ 1 }{ 2 }\right)e^{2x}+\left(\frac{ 1 }{ 2 }\right)e^{-2x}-2x\right)_0^1\]

  18. zepdrix
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    maybe the problem is... are you forgetting, its a DEFINITE integral.. or you're having trouble before that part? :D

  19. Dido525
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I got it!!!

  20. zepdrix
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh good :3 lol

  21. Dido525
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    If you were wondering it is: |dw:1353112228539:dw|

  22. zepdrix
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh cool c:

  23. Dido525
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    No constant right? It's a definite integral.

  24. Dido525
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @zepdrix

  25. zepdrix
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yah any constants would fall out c: no constant.

  26. Not the answer you are looking for?
    Search for more explanations.

    Search OpenStudy
    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.