anonymous
  • anonymous
Hyperbolic intergal
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1353111163841:dw|
anonymous
  • anonymous
No matter how many times I do it I keep getting the wrong answer.
anonymous
  • anonymous
@zepdrix

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More answers

anonymous
  • anonymous
I believe the anti-derivative is: |dw:1353111289980:dw|
zepdrix
  • zepdrix
Hmm I'm not sure how you're able to deal with the fact that the outside term is a square. Is there a double angle formula for hyperbolic sine? Otherwise I would convert to exponentials and break it down from there. \[\large \sinh x=\frac{ e^x-e^{-x} }{ 2 }\] \[\large \sinh^2 x=\left(\frac{ e^x-e^{-x} }{ 2 }\right)^2=\left(\frac{ 1 }{ 4 }\right)(e^{2x}-e^{-2x}-2)\] Hopefully I expanded that correctly :O
anonymous
  • anonymous
Well according to Wikipedia:
1 Attachment
anonymous
  • anonymous
In this case a is 1.
zepdrix
  • zepdrix
Hmm yah it looks good. But if you're trying to enter this into webassign (or something similar), then maybe your teacher is looking for an answer in exponential form. Hmmmmm.
anonymous
  • anonymous
No No. It's a written :) .
zepdrix
  • zepdrix
Do you have the answer we're SUPPOSE to get, like in a book or anything? :D
anonymous
  • anonymous
No...
zepdrix
  • zepdrix
Then why do you think you're getting the wrong answer? XD
zepdrix
  • zepdrix
Oh, so you GAVE me the answer, you're just not sure how to get there? :O
anonymous
  • anonymous
Wolfram.
anonymous
  • anonymous
Ohh wait...
anonymous
  • anonymous
No I didn't give you the answer. I just keep getting different answers every time.
zepdrix
  • zepdrix
\[\huge \int\limits_{0}^{1}\left(\frac{ 1 }{ 4 }\right)(e^{2x}-e^{-2x}-2) dx\] \[\huge =\left(\frac{ 1 }{ 4 }\right)\left(\left(\frac{ 1 }{ 2 }\right)e^{2x}+\left(\frac{ 1 }{ 2 }\right)e^{-2x}-2x\right)_0^1\]
zepdrix
  • zepdrix
maybe the problem is... are you forgetting, its a DEFINITE integral.. or you're having trouble before that part? :D
anonymous
  • anonymous
I got it!!!
zepdrix
  • zepdrix
oh good :3 lol
anonymous
  • anonymous
If you were wondering it is: |dw:1353112228539:dw|
zepdrix
  • zepdrix
oh cool c:
anonymous
  • anonymous
No constant right? It's a definite integral.
anonymous
  • anonymous
@zepdrix
zepdrix
  • zepdrix
Yah any constants would fall out c: no constant.

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