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Dido525
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Find the intervals on which the function f(x) is increasing.
 2 years ago
 2 years ago
Dido525 Group Title
Find the intervals on which the function f(x) is increasing.
 2 years ago
 2 years ago

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Dido525 Group TitleBest ResponseYou've already chosen the best response.0
dw:1353112573724:dw
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
@zepdrix . I believe I would find the derivative using FTC and then antiderivative that to find f(x) right?
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
I think you're half right, I think you want to do the first half of what you said.
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
\[\large f(x)=\int\limits_{0}^{x}(1+t^2)e^{t^2}dt\] \[\huge f'(x)=(1+x^2)e^{x^2}\]
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Then just find critical points to find your intervals... i think :O
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Yeah, but wouldn't I also need to know what f(x) is?
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Actually... I wouldn't right? All I need is the derivative.
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Yah I don't think they want us to SOLVE for f(x). They've given us f(x), it just looks a little funny. We simply want intervals of increasing/decreasing. So we only need to deal with f'(x).
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Thanks :) .
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Guess it's my OCD telling me to find f(x) .
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Hmm i could be wrong, but I don't think you can actually solve that integral using elementary methods :D heh
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
because of the e^t^2 term :o
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Yeah, guess so.
 2 years ago
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