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sthop456
 2 years ago
Best ResponseYou've already chosen the best response.0Don't know if this is right, but if you are looking for the limit of cos^2(x), cos(x) oscillates between 1 and 1, so squaring it would still oscillate it between 0 and 1, so the limit would not exist, DNE (does not exist). Not sure, though.

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.0\[\cos^2(\theta)=\frac12\left(\cos(2\theta)1\right)\]

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.0\[\mathcal L\Big\{ \cos^2\theta\Big\}=\frac12\left(\mathcal L\Big\{ \cos2\theta\Big\}\mathcal L\Big\{1\Big\}\right)\]

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.0tell me what you get @psk981
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